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Adjoint representation
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==Definition== {{see also|Representation theory|Lie group#The Lie algebra associated with a Lie group}} Let ''G'' be a [[Lie group]], and let :<math>\Psi: G \to \operatorname{Aut}(G)</math> be the mapping {{math|''g'' ↦ Ψ<sub>''g''</sub>}}, with Aut(''G'') the [[automorphism group]] of ''G'' and {{math|Ψ<sub>''g''</sub>: ''G'' → ''G''}} given by the [[inner automorphism]] (conjugation) :<math>\Psi_g(h)= ghg^{-1}~.</math> This Ψ is a [[Lie_group#Homomorphisms_and_isomorphisms|Lie group homomorphism]]. For each ''g'' in ''G'', define {{math|Ad<sub>''g''</sub>}} to be the [[tangent space|derivative]] of {{math|Ψ<sub>''g''</sub>}} at the origin: :<math>\operatorname{Ad}_g = (d\Psi_g)_e : T_eG \rightarrow T_eG</math> where {{mvar|d}} is the differential and <math>\mathfrak{g} = T_e G</math> is the [[tangent space]] at the origin {{mvar|e}} ({{mvar|e}} being the identity element of the group {{mvar|G}}). Since <math>\Psi_g</math> is a Lie group automorphism, Ad<sub>''g''</sub> is a [[Lie algebra automorphism]]; i.e., an invertible [[linear transformation]] of <math>\mathfrak g</math> to itself that preserves the [[Lie algebra#Definitions|Lie bracket]]. Moreover, since <math>g \mapsto \Psi_g</math> is a group homomorphism, <math>g \mapsto \operatorname{Ad}_g</math> too is a group homomorphism.<ref>Indeed, by the [[chain rule]], <math>\operatorname{Ad}_{gh} = d (\Psi_{gh})_e = d (\Psi_g \circ \Psi_h)_e = d (\Psi_g)_e \circ d (\Psi_h)_e = \operatorname{Ad}_g \circ \operatorname{Ad}_h.</math></ref> Hence, the map :<math>\mathrm{Ad}\colon G \to \mathrm{Aut}(\mathfrak g), \, g \mapsto \mathrm{Ad}_g</math> is a [[group representation]] called the '''adjoint representation''' of ''G''. If ''G'' is an [[Lie_group–Lie_algebra_correspondence#Homomorphisms|immersed Lie subgroup]] of the general linear group <math>\mathrm{GL}_n(\mathbb{C})</math> (called immersely linear Lie group), then the Lie algebra <math>\mathfrak{g}</math> consists of matrices and the [[exponential map (Lie theory)|exponential map]] is the matrix exponential <math>\operatorname{exp}(X) = e^X</math> for matrices ''X'' with small operator norms. We will compute the derivative of <math>\Psi_g</math> at <math>e</math>. For ''g'' in ''G'' and small ''X'' in <math>\mathfrak{g}</math>, the curve <math>t\to \exp(tX)</math> has derivative <math>X</math> at ''t'' = 0, one then gets: :<math>\operatorname{Ad}_g(X) = (d\Psi_g)_e (X)=(\Psi_g\circ \exp(tX))'(0)=(g\exp(tX)g^{-1})'(0)=gX g^{-1}</math> where on the right we have the products of matrices. If <math>G \subset \mathrm{GL}_n(\mathbb{C})</math> is a closed subgroup (that is, ''G'' is a matrix Lie group), then this formula is valid for all ''g'' in ''G'' and all ''X'' in <math>\mathfrak g</math>. Succinctly, an adjoint representation is an [[isotropy representation]] associated to the conjugation action of ''G'' around the identity element of ''G''. ===Derivative of Ad=== One may always pass from a representation of a Lie group ''G'' to a [[representation of a Lie algebra|representation of its Lie algebra]] by taking the derivative at the identity. Taking the derivative of the adjoint map :<math>\mathrm{Ad} : G \to \mathrm{Aut}(\mathfrak g)</math> at the identity element gives the '''adjoint representation''' of the Lie algebra <math>\mathfrak g = \operatorname{Lie}(G)</math> of ''G'': :<math>\begin{align} \mathrm{ad} : & \, \mathfrak g \to \mathrm{Der}(\mathfrak g) \\ & \,x \mapsto \operatorname{ad}_x = d(\operatorname{Ad})_e(x) \end{align}</math> where <math>\mathrm{Der}(\mathfrak g) = \operatorname{Lie}(\operatorname{Aut}(\mathfrak{g}))</math> is the Lie algebra of <math>\mathrm{Aut}(\mathfrak g)</math> which may be identified with the [[differential algebra#Lie algebra|derivation algebra]] of <math>\mathfrak g</math>. One can show that :<math>\mathrm{ad}_x(y) = [x,y]\,</math> for all <math>x,y \in \mathfrak g</math>, where the right hand side is given (induced) by the [[Lie bracket of vector fields]]. Indeed,<ref>{{harvnb|Kobayashi|Nomizu|1996|loc=page 41}}</ref> recall that, viewing <math>\mathfrak{g}</math> as the Lie algebra of left-invariant vector fields on ''G'', the bracket on <math>\mathfrak g</math> is given as:<ref>{{harvnb|Kobayashi|Nomizu|1996|loc=Proposition 1.9.}}</ref> for left-invariant vector fields ''X'', ''Y'', :<math>[X, Y] = \lim_{t \to 0} {1 \over t}(d \varphi_{-t}(Y) - Y)</math> where <math>\varphi_t: G \to G</math> denotes the [[flow (mathematics)|flow]] generated by ''X''. As it turns out, <math>\varphi_t(g) = g\varphi_t(e)</math>, roughly because both sides satisfy the same ODE defining the flow. That is, <math>\varphi_t = R_{\varphi_t(e)}</math> where <math>R_h</math> denotes the right multiplication by <math>h \in G</math>. On the other hand, since <math>\Psi_g = R_{g^{-1}} \circ L_g</math>, by the [[chain rule]], :<math>\operatorname{Ad}_g(Y) = d (R_{g^{-1}} \circ L_g)(Y) = d R_{g^{-1}} (d L_g(Y)) = d R_{g^{-1}}(Y)</math> as ''Y'' is left-invariant. Hence, :<math>[X, Y] = \lim_{t \to 0} {1 \over t}(\operatorname{Ad}_{\varphi_t(e)}(Y) - Y)</math>, which is what was needed to show. Thus, <math>\mathrm{ad}_x</math> coincides with the same one defined in {{section link||Adjoint representation of a Lie algebra}} below. Ad and ad are related through the [[exponential map (Lie theory)|exponential map]]: Specifically, Ad<sub>exp(''x'')</sub> = exp(ad<sub>''x''</sub>) for all ''x'' in the Lie algebra.<ref>{{harvnb|Hall|2015}} Proposition 3.35</ref> It is a consequence of the general result relating Lie group and Lie algebra homomorphisms via the exponential map.<ref>{{harvnb|Hall|2015}} Theorem 3.28</ref> If ''G'' is an immersely linear Lie group, then the above computation simplifies: indeed, as noted early, <math>\operatorname{Ad}_g(Y) = gYg^{-1}</math> and thus with <math>g = e^{tX}</math>, :<math>\operatorname{Ad}_{e^{tX}}(Y) = e^{tX} Y e^{-tX}</math>. Taking the derivative of this at <math>t = 0</math>, we have: :<math>\operatorname{ad}_X Y = XY - YX</math>. The general case can also be deduced from the linear case: indeed, let <math>G'</math> be an immersely linear Lie group having the same Lie algebra as that of ''G''. Then the derivative of Ad at the identity element for ''G'' and that for ''G{{'}}'' coincide; hence, without loss of generality, ''G'' can be assumed to be ''G{{'}}''. The upper-case/lower-case notation is used extensively in the literature. Thus, for example, a vector {{mvar|x}} in the algebra <math>\mathfrak{g}</math> generates a [[vector field]] {{mvar|X}} in the group {{mvar|G}}. Similarly, the adjoint map {{math|ad<sub>x</sub>y {{=}} [''x'',''y'']}} of vectors in <math>\mathfrak{g}</math> is homomorphic{{clarify|map is homomorphic??|date=December 2018}} to the [[Lie derivative]] {{math|L<sub>''X''</sub>''Y'' {{=}} [''X'',''Y'']}} of vector fields on the group {{mvar|G}} considered as a [[manifold]]. Further see the [[derivative of the exponential map]].
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