Open main menu
Home
Random
Recent changes
Special pages
Community portal
Preferences
About Wikipedia
Disclaimers
Incubator escapee wiki
Search
User menu
Talk
Dark mode
Contributions
Create account
Log in
Editing
Arthur–Merlin protocol
(section)
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
==MA== The simplest such protocol is the 1-message protocol where Merlin sends Arthur a message, and then Arthur decides whether to accept or not by running a probabilistic polynomial time computation. (This is similar to the verifier-based definition of NP, the only difference being that Arthur is allowed to use randomness here.) Merlin does not have access to Arthur's coin tosses in this protocol, since it is a single-message protocol and Arthur tosses his coins only after receiving Merlin's message. This protocol is called ''MA''. Informally, a [[formal language|language]] ''L'' is in '''MA''' if for all strings in the language, there is a polynomial sized proof that Merlin can send Arthur to convince him of this fact with high probability, and for all strings not in the language there is no proof that convinces Arthur with high probability. Formally, the complexity class '''MA''' is the set of decision problems that can be decided in polynomial time by an Arthur–Merlin protocol where Merlin's only move precedes any computation by Arthur. In other words, a language ''L'' is in '''MA''' if there exists a polynomial-time deterministic Turing machine ''M'' and polynomials ''p'', ''q'' such that for every input string ''x'' of length ''n'' = |''x''|, *if ''x'' is in ''L'', then <math>\exists z\in\{0,1\}^{q(n)}\,\Pr\nolimits_{y\in\{0,1\}^{p(n)}}(M(x,y,z)=1)\ge2/3,</math> *if ''x'' is not in ''L'', then <math>\forall z\in\{0,1\}^{q(n)}\,\Pr\nolimits_{y\in\{0,1\}^{p(n)}}(M(x,y,z)=0)\ge2/3.</math> The second condition can alternatively be written as *if ''x'' is not in ''L'', then <math>\forall z\in\{0,1\}^{q(n)}\,\Pr\nolimits_{y\in\{0,1\}^{p(n)}}(M(x,y,z)=1)\le1/3.</math> To compare this with the informal definition above, ''z'' is the purported proof from Merlin (whose size is bounded by a polynomial) and ''y'' is the random string that Arthur uses, which is also polynomially bounded.
Edit summary
(Briefly describe your changes)
By publishing changes, you agree to the
Terms of Use
, and you irrevocably agree to release your contribution under the
CC BY-SA 4.0 License
and the
GFDL
. You agree that a hyperlink or URL is sufficient attribution under the Creative Commons license.
Cancel
Editing help
(opens in new window)