Open main menu
Home
Random
Recent changes
Special pages
Community portal
Preferences
About Wikipedia
Disclaimers
Incubator escapee wiki
Search
User menu
Talk
Dark mode
Contributions
Create account
Log in
Editing
Chaplygin's equation
(section)
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
==Derivation== For two-dimensional [[potential flow]], the continuity equation and the [[Euler equations (fluid dynamics)|Euler equations]] (in fact, the [[Bernoulli's principle#Compressible flow equation|compressible Bernoulli's equation]] due to irrotationality) in Cartesian coordinates <math>(x,y)</math> involving the variables fluid velocity <math>(v_x,v_y)</math>, [[specific enthalpy]] <math>h</math> and density <math>\rho</math> are :<math> \begin{align} \frac{\partial }{\partial x}(\rho v_x) + \frac{\partial }{\partial y}(\rho v_y) &=0,\\ h + \frac{1}{2}v^2 &= h_o. \end{align} </math> with the [[equation of state]] <math>\rho=\rho(s,h)</math> acting as third equation. Here <math>h_o</math> is the stagnation enthalpy, <math>v^2 = v_x^2 + v_y^2</math> is the magnitude of the velocity vector and <math>s</math> is the entropy. For [[isentropic]] flow, density can be expressed as a function only of enthalpy <math>\rho=\rho(h)</math>, which in turn using Bernoulli's equation can be written as <math>\rho=\rho(v)</math>. Since the flow is irrotational, a velocity potential <math>\phi</math> exists and its differential is simply <math>d\phi = v_x dx + v_y dy</math>. Instead of treating <math>v_x=v_x(x,y)</math> and <math>v_y=v_y(x,y)</math> as dependent variables, we use a coordinate transform such that <math>x=x(v_x,v_y)</math> and <math>y=y(v_x,v_y)</math> become new dependent variables. Similarly the [[velocity potential]] is replaced by a new function ([[Legendre transformation]])<ref>{{cite book|last1=Landau|first1=L. D.|authorlink1=Lev Landau|last2=Lifshitz|first2=E. M.|authorlink2=Evgeny Lifshitz|title=Fluid Mechanics|edition=2|year=1982|publisher=Pergamon Press|page=432}}</ref> :<math>\Phi = xv_x + yv_y - \phi</math> such then its differential is <math>d\Phi = xdv_x + y dv_y</math>, therefore :<math>x = \frac{\partial \Phi}{\partial v_x}, \quad y = \frac{\partial \Phi}{\partial v_y}.</math> Introducing another coordinate transformation for the independent variables from <math>(v_x,v_y)</math> to <math>(v,\theta)</math> according to the relation <math>v_x = v\cos\theta</math> and <math>v_y = v\sin\theta</math>, where <math>v</math> is the magnitude of the velocity vector and <math>\theta</math> is the angle that the velocity vector makes with the <math>v_x</math>-axis, the dependent variables become :<math> \begin{align} x &= \cos\theta \frac{\partial \Phi}{\partial v}-\frac{\sin\theta}{v}\frac{\partial \Phi}{\partial \theta},\\ y &= \sin\theta \frac{\partial \Phi}{\partial v}+\frac{\cos\theta}{v}\frac{\partial \Phi}{\partial \theta},\\ \phi & = -\Phi + v\frac{\partial \Phi}{\partial v}. \end{align} </math> The continuity equation in the new coordinates become :<math>\frac{d(\rho v)}{dv} \left(\frac{\partial \Phi}{\partial v} + \frac{1}{v} \frac{\partial^2 \Phi}{\partial \theta^2}\right) + \rho v \frac{\partial^2 \Phi}{\partial v^2} =0.</math> For isentropic flow, <math>dh=\rho^{-1}c^2 d\rho</math>, where <math>c</math> is the speed of sound. Using the Bernoulli's equation we find :<math>\frac{d(\rho v)}{d v} = \rho \left(1-\frac{v^2}{c^2}\right)</math> where <math>c=c(v)</math>. Hence, we have :<math> \frac{\partial^2 \Phi}{\partial \theta^2} + \frac{v^2}{1-\frac{v^2}{c^2}}\frac{\partial^2 \Phi}{\partial v^2}+v \frac{\partial \Phi}{\partial v}=0.</math>
Edit summary
(Briefly describe your changes)
By publishing changes, you agree to the
Terms of Use
, and you irrevocably agree to release your contribution under the
CC BY-SA 4.0 License
and the
GFDL
. You agree that a hyperlink or URL is sufficient attribution under the Creative Commons license.
Cancel
Editing help
(opens in new window)