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Disjoint union
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== Example == Consider the sets <math>A_0 = \{5, 6, 7\}</math> and <math>A_1 = \{5, 6\}.</math> It is possible to index the set elements according to set origin by forming the associated sets <math>\begin{align} A^*_0 & = \{(5, 0), (6, 0), (7, 0)\} \\ A^*_1 & = \{(5, 1), (6, 1)\}, \\ \end{align} </math> where the second element in each pair matches the subscript of the origin set (for example, the <math>0</math> in <math>(5, 0)</math> matches the subscript in <math>A_0,</math> etc.). The disjoint union <math>A_0 \sqcup A_1</math> can then be calculated as follows: <math display="block">A_0 \sqcup A_1 = A^*_0 \cup A^*_1 = \{(5, 0), (6, 0), (7, 0), (5, 1), (6, 1)\}.</math>
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