Open main menu
Home
Random
Recent changes
Special pages
Community portal
Preferences
About Wikipedia
Disclaimers
Incubator escapee wiki
Search
User menu
Talk
Dark mode
Contributions
Create account
Log in
Editing
Envelope (mathematics)
(section)
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
==Envelope of a family of curves== Let each curve ''C''<sub>''t''</sub> in the family be given as the solution of an equation ''f''<sub>''t''</sub>(''x'', ''y'')=0 (see [[implicit curve]]), where ''t'' is a parameter. Write ''F''(''t'', ''x'', ''y'')=''f''<sub>''t''</sub>(''x'', ''y'') and assume ''F'' is differentiable. The envelope of the family ''C''<sub>''t''</sub> is then defined as the set <math>\mathcal{D}</math> of points (''x'',''y'') for which, simultaneously, :<math>F(t, x, y) = 0~~\mathsf{and}~~{\partial F \over \partial t}(t, x, y) = 0</math> for some value of ''t'', where <math>\partial F/\partial t</math> is the [[partial derivative]] of ''F'' with respect to ''t''.<ref>{{Citation |first=J. W. |last=Bruce |first2=P. J. |last2=Giblin |title=Curves and Singularities |publisher=Cambridge University Press |year=1984 |ISBN=0-521-42999-4}}</ref> If ''t'' and ''u'', ''t''≠''u'' are two values of the parameter then the intersection of the curves ''C''<sub>''t''</sub> and ''C''<sub>''u''</sub> is given by :<math>F(t, x, y) = F(u, x, y) = 0\,</math> or, equivalently, :<math>F(t, x, y) = 0~~\mathsf{and}~~\frac{F(u, x, y)-F(t, x, y)}{u-t} = 0.</math> Letting ''u'' → ''t'' gives the definition above. An important special case is when ''F''(''t'', ''x'', ''y'') is a polynomial in ''t''. This includes, by [[clearing denominators]], the case where ''F''(''t'', ''x'', ''y'') is a rational function in ''t''. In this case, the definition amounts to ''t'' being a double root of ''F''(''t'', ''x'', ''y''), so the equation of the envelope can be found by setting the [[discriminant]] of ''F'' to 0 (because the definition demands F=0 at some t and first derivative =0 i.e. its value 0 and it is min/max at that t). For example, let ''C''<sub>''t''</sub> be the line whose ''x'' and ''y'' intercepts are ''t'' and 11−''t'', this is shown in the animation above. The equation of ''C''<sub>''t''</sub> is :<math>\frac{x}{t}+\frac{y}{11-t}=1</math> or, clearing fractions, :<math>x(11-t)+yt-t(11-t)=t^2+(-x+y-11)t+11x=0.\,</math> The equation of the envelope is then :<math>(-x+y-11)^2-44x=(x-y)^2-22(x+y)+121=0.\,</math> Often when ''F'' is not a rational function of the parameter it may be reduced to this case by an appropriate substitution. For example, if the family is given by ''C''<sub>θ</sub> with an equation of the form ''u''(''x'', ''y'')cos θ+''v''(''x'', ''y'')sin θ=''w''(''x'', ''y''), then putting ''t''=''e''<sup>''i''θ</sup>, cos θ=(''t''+1/''t'')/2, sin θ=(''t''-1/''t'')/2''i'' changes the equation of the curve to :<math>u{1 \over 2}(t+{1\over t})+v{1 \over 2i}(t-{1\over t})=w</math> or :<math>(u-iv)t^2-2wt+(u+iv)=0.\,</math> The equation of the envelope is then given by setting the discriminant to 0: :<math>(u-iv)(u+iv)-w^2=0\,</math> or :<math>u^2+v^2=w^2.\,</math> ===Alternative definitions=== # The envelope ''E''<sub>1</sub> is the limit of intersections of nearby curves ''C''<sub>''t''</sub>. # The envelope ''E''<sub>2</sub> is a curve tangent to all of the ''C''<sub>''t''</sub>. # The envelope ''E''<sub>3</sub> is the boundary of the region filled by the curves ''C''<sub>''t''</sub>. Then <math>E_1 \subseteq \mathcal{D}</math>, <math>E_2 \subseteq \mathcal{D}</math> and <math>E_3 \subseteq \mathcal{D}</math>, where <math>\mathcal{D}</math> is the set of points defined at the beginning of this subsection's parent section.
Edit summary
(Briefly describe your changes)
By publishing changes, you agree to the
Terms of Use
, and you irrevocably agree to release your contribution under the
CC BY-SA 4.0 License
and the
GFDL
. You agree that a hyperlink or URL is sufficient attribution under the Creative Commons license.
Cancel
Editing help
(opens in new window)