Open main menu
Home
Random
Recent changes
Special pages
Community portal
Preferences
About Wikipedia
Disclaimers
Incubator escapee wiki
Search
User menu
Talk
Dark mode
Contributions
Create account
Log in
Editing
Heyting algebra
(section)
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
===Provable identities=== Given a formula <math>F(A_1, A_2,\ldots, A_n)</math> of propositional calculus (using, in addition to the variables, the connectives <math>\land, \lor, \lnot, \to</math>, and the constants 0 and 1), it is a fact, proved early on in any study of Heyting algebras, that the following two conditions are equivalent: # The formula ''F'' is provably true in intuitionist propositional calculus. # The identity <math>F(a_1, a_2,\ldots, a_n) = 1</math> is true for any Heyting algebra ''H'' and any elements <math>a_1, a_2,\ldots, a_n \in H</math>. The metaimplication {{nowrap|1 β 2}} is extremely useful and is the principal practical method for proving identities in Heyting algebras. In practice, one frequently uses the [[deduction theorem]] in such proofs. Since for any ''a'' and ''b'' in a Heyting algebra ''H'' we have <math>a \le b</math> if and only if ''a''β''b'' = 1, it follows from {{nowrap|1 β 2}} that whenever a formula ''F''β''G'' is provably true, we have <math>F(a_1, a_2,\ldots, a_n) \le G(a_1, a_2,\ldots, a_n)</math> for any Heyting algebra ''H'', and any elements <math>a_1, a_2,\ldots, a_n \in H</math>. (It follows from the deduction theorem that ''F''β''G'' is provable (unconditionally) if and only if ''G'' is provable from ''F'', that is, if ''G'' is a provable consequence of ''F''.) In particular, if ''F'' and ''G'' are provably equivalent, then <math>F(a_1, a_2,\ldots, a_n) = G(a_1, a_2,\ldots, a_n)</math>, since β€ is an order relation. 1 β 2 can be proved by examining the logical axioms of the system of proof and verifying that their value is 1 in any Heyting algebra, and then verifying that the application of the rules of inference to expressions with value 1 in a Heyting algebra results in expressions with value 1. For example, let us choose the system of proof having [[modus ponens]] as its sole rule of inference, and whose axioms are the Hilbert-style ones given at [[Intuitionistic logic#Axiomatization]]. Then the facts to be verified follow immediately from the axiom-like definition of Heyting algebras given above. 1 β 2 also provides a method for proving that certain propositional formulas, though [[tautology (logic)|tautologies]] in classical logic, ''cannot'' be proved in intuitionist propositional logic. In order to prove that some formula <math>F(A_1, A_2,\ldots, A_n)</math> is not provable, it is enough to exhibit a Heyting algebra ''H'' and elements <math>a_1, a_2,\ldots, a_n \in H</math> such that <math>F(a_1, a_2,\ldots, a_n) \ne 1</math>. If one wishes to avoid mention of logic, then in practice it becomes necessary to prove as a lemma a version of the deduction theorem valid for Heyting algebras: for any elements ''a'', ''b'' and ''c'' of a Heyting algebra ''H'', we have <math>(a \land b) \to c = a \to (b \to c)</math>. For more on the metaimplication 2 β 1, see the section "[[#Universal constructions|Universal constructions]]" below.
Edit summary
(Briefly describe your changes)
By publishing changes, you agree to the
Terms of Use
, and you irrevocably agree to release your contribution under the
CC BY-SA 4.0 License
and the
GFDL
. You agree that a hyperlink or URL is sufficient attribution under the Creative Commons license.
Cancel
Editing help
(opens in new window)