Open main menu
Home
Random
Recent changes
Special pages
Community portal
Preferences
About Wikipedia
Disclaimers
Incubator escapee wiki
Search
User menu
Talk
Dark mode
Contributions
Create account
Log in
Editing
Logistic regression
(section)
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
===Model evaluation=== The logistic regression analysis gives the following output. {| class="wikitable" |- ! !! Coefficient!! Std. Error !! ''z''-value !! ''p''-value (Wald) |- style="text-align:right;" ! Intercept (''Ξ²''<sub>0</sub>) | β4.1 || 1.8 || β2.3 || 0.021 |- style="text-align:right;" ! Hours (''Ξ²''<sub>1</sub>) | 1.5 || 0.9 || 1.7 || 0.017 |} By the [[Wald test]], the output indicates that hours studying is significantly associated with the probability of passing the exam (<math>p = 0.017</math>). Rather than the Wald method, the recommended method<ref name="NeymanPearson1933">{{citation | last1 = Neyman | first1 = J. | author-link1 = Jerzy Neyman| last2 = Pearson | first2 = E. S. | author-link2 = Egon Pearson| doi = 10.1098/rsta.1933.0009 | title = On the problem of the most efficient tests of statistical hypotheses | journal = [[Philosophical Transactions of the Royal Society of London A]] | volume = 231 | issue = 694β706 | pages = 289β337 | year = 1933 | jstor = 91247 |bibcode = 1933RSPTA.231..289N | url = http://www.stats.org.uk/statistical-inference/NeymanPearson1933.pdf | doi-access = free }}</ref> to calculate the ''p''-value for logistic regression is the [[likelihood-ratio test]] (LRT), which for these data give <math>p \approx 0.00064</math> (see {{slink||Deviance and likelihood ratio tests}} below).
Edit summary
(Briefly describe your changes)
By publishing changes, you agree to the
Terms of Use
, and you irrevocably agree to release your contribution under the
CC BY-SA 4.0 License
and the
GFDL
. You agree that a hyperlink or URL is sufficient attribution under the Creative Commons license.
Cancel
Editing help
(opens in new window)