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Projectile motion
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=== Relation between horizontal range and maximum height === The relation between the range <var>d</var> on the horizontal plane and the maximum height <var>h</var> reached at <math> \frac{t_d}{2} </math> is: :<math> h = \frac{d\tan\theta}{4} </math> {{Collapse top|title=Proof}} <math> h = \frac{v_0^2\sin^2\theta}{2|g|} </math> :<math> d = \frac{v_0^2\sin2\theta}{|g|} </math> :<math> \frac{h}{d} = \frac{v_0^2\sin^2\theta}{2|g|} </math> Γ <math> \frac{g}{v_0^2\sin2\theta} </math> :<math> \frac{h}{d} = \frac{\sin^2\theta}{4\sin\theta\cos\theta} </math> <math> h = \frac{d\tan\theta}{4} </math>. If <math>h = R</math> :'''<math> \theta = \arctan(4)\approx 76.0^\circ </math>''' {{Collapse bottom|}}
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