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Quadratic function
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===Vertex===<!-- This section is linked from [[Quadratic equation]] --> The '''vertex''' of a parabola is the place where it turns; hence, it is also called the '''turning point'''. If the quadratic function is in vertex form, the vertex is {{math|(''h'', ''k'')}}. Using the method of completing the square, one can turn the standard form :<math>f(x) = a x^2 + b x + c</math> into : <math>\begin{align} f(x) &= a x^2 + b x + c \\ &= a (x - h)^2 + k \\ &= a\left(x - \frac{-b}{2a}\right)^2 + \left(c - \frac{b^2}{4a}\right),\\ \end{align}</math> so the vertex, {{math|(''h'', ''k'')}}, of the parabola in standard form is : <math> \left(-\frac{b}{2a}, c - \frac{b^2}{4a}\right). </math>{{Citation needed|date=October 2022}} If the quadratic function is in factored form :<math>f(x) = a(x - r_1)(x - r_2)</math> the average of the two roots, i.e., : <math>\frac{r_1 + r_2}{2}</math> is the {{math|''x''}}-coordinate of the vertex, and hence the vertex {{math|(''h'', ''k'')}} is : <math> \left(\frac{r_1 + r_2}{2}, f\left(\frac{r_1 + r_2}{2}\right)\right).</math> The vertex is also the maximum point if {{math|''a'' < 0}}, or the minimum point if {{math|''a'' > 0}}. The vertical line : <math> x=h=-\frac{b}{2a} </math> that passes through the vertex is also the '''axis of symmetry''' of the parabola. ====Maximum and minimum points==== Using [[calculus]], the vertex point, being a [[minima and maxima|maximum or minimum]] of the function, can be obtained by finding the roots of the [[derivative]]: :<math>f(x)=ax^2+bx+c \quad \Rightarrow \quad f'(x)=2ax+b</math> {{math|''x''}} is a root of {{math|''f'' '(''x'')}} if {{math|''f'' '(''x'') {{=}} 0}} resulting in :<math>x=-\frac{b}{2a}</math> with the corresponding function value :<math>f(x) = a \left (-\frac{b}{2a} \right)^2+b \left (-\frac{b}{2a} \right)+c = c-\frac{b^2}{4a},</math> so again the vertex point coordinates, {{math|(''h'', ''k'')}}, can be expressed as :<math> \left (-\frac {b}{2a}, c-\frac {b^2}{4a} \right). </math>
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