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Weak topology
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=== Properties === If {{mvar|X}} is a [[Separable space|separable]] (i.e. has a countable dense subset) [[locally convex]] space and ''H'' is a norm-bounded subset of its continuous dual space, then ''H'' endowed with the weak* (subspace) topology is a [[metrizable]] topological space.{{sfn | Narici | Beckenstein | 2011 | pp=225-273}} However, for infinite-dimensional spaces, the metric cannot be translation-invariant.{{sfn | Folland | 1999 | pp=170}} If {{mvar|X}} is a separable [[Metrizable TVS|metrizable]] [[locally convex]] space then the weak* topology on the continuous dual space of {{mvar|X}} is separable.{{sfn | Narici | Beckenstein | 2011 | pp=225-273}} ;Properties on normed spaces By definition, the weak* topology is weaker than the weak topology on <math>X^*</math>. An important fact about the weak* topology is the [[Banach–Alaoglu theorem]]: if {{mvar|X}} is normed, then the closed unit ball in <math>X^*</math> is weak*-[[compact space|compact]] (more generally, the [[polar set|polar]] in <math>X^*</math> of a neighborhood of 0 in {{mvar|X}} is weak*-compact). Moreover, the closed unit ball in a normed space {{mvar|X}} is compact in the weak topology if and only if {{mvar|X}} is [[reflexive space|reflexive]]. In more generality, let {{mvar|F}} be locally compact valued field (e.g., the reals, the complex numbers, or any of the p-adic number systems). Let {{mvar|X}} be a normed topological vector space over {{mvar|F}}, compatible with the absolute value in {{mvar|F}}. Then in <math>X^*</math>, the topological dual space {{mvar|X}} of continuous {{mvar|F}}-valued linear functionals on {{mvar|X}}, all norm-closed balls are compact in the weak* topology. If {{mvar|X}} is a normed space, a version of the [[Heine-Borel theorem]] holds. In particular, a subset of the continuous dual is weak* compact if and only if it is weak* closed and norm-bounded.{{sfn | Narici | Beckenstein | 2011 | pp=225-273}} This implies, in particular, that when {{mvar|X}} is an infinite-dimensional normed space then the closed unit ball at the origin in the dual space of {{mvar|X}} does not contain any weak* neighborhood of 0 (since any such neighborhood is norm-unbounded).{{sfn | Narici | Beckenstein | 2011 | pp=225-273}} Thus, even though norm-closed balls are compact, X* is not weak* [[locally compact space|locally compact]]. If {{mvar|X}} is a normed space, then {{mvar|X}} is separable if and only if the weak* topology on the closed unit ball of <math>X^*</math> is metrizable,{{sfn | Narici | Beckenstein | 2011 | pp=225-273}} in which case the weak* topology is metrizable on norm-bounded subsets of <math>X^*</math>. If a normed space {{mvar|X}} has a dual space that is separable (with respect to the dual-norm topology) then {{mvar|X}} is necessarily separable.{{sfn | Narici | Beckenstein | 2011 | pp=225-273}} If {{mvar|X}} is a [[Banach space]], the weak* topology is not metrizable on all of <math>X^*</math> unless {{mvar|X}} is finite-dimensional.<ref>Proposition 2.6.12, p. 226 in {{citation | last = Megginson | first = Robert E. | author-link = Robert Megginson | title = An introduction to Banach space theory | series = Graduate Texts in Mathematics | volume = 183 | publisher = Springer-Verlag | location = New York | year = 1998 | pages = xx+596 | isbn = 0-387-98431-3}}.</ref>
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