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Stack machine
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===Pipelining=== In modern machines, the time to fetch a variable from the data cache is often several times longer than the time needed for basic ALU operations. A program runs faster without stalls if its memory loads can be started several cycles before the instruction that needs that variable. Complex machines can do this with a deep pipeline and "out-of-order execution" that examines and runs many instructions at once. Register machines can even do this with much simpler "in-order" hardware, a shallow pipeline, and slightly smarter compilers. The load step becomes a separate instruction, and that instruction is statically scheduled much earlier in the code sequence. The compiler puts independent steps in between. Scheduling memory accesses requires explicit, spare registers. It is not possible on stack machines without exposing some aspect of the micro-architecture to the programmer. For the expression A B -, B must be evaluated and pushed immediately prior to the Minus step. Without stack permutation or hardware multithreading, relatively little useful code can be put in between while waiting for the Load B to finish. Stack machines can work around the memory delay by either having a deep out-of-order execution pipeline covering many instructions at once, or more likely, they can permute the stack such that they can work on other workloads while the load completes, or they can interlace the execution of different program threads, as in the Unisys A9 system.<ref name="Burroughs_1986"/> Today's increasingly parallel computational loads suggests, however, this might not be the disadvantage it's been made out to be in the past. Stack machines can omit the operand fetching stage of a register machine.<ref name="Koopman_1989"/> For example, in the [[Java Optimized Processor]] (JOP) microprocessor the top 2 operands of stack directly enter a data forwarding circuit that is faster than the register file.<ref name="Jopdesign"/>
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