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Cross section (physics)
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=== Elastic collision of two hard spheres === The following equations apply to two hard spheres that undergo a perfectly elastic collision.{{sfn | Taylor | 2005 | pp=564,574}} Let {{math|''R''}} and {{math|''r''}} denote the radii of the scattering center and scattered sphere, respectively. The differential cross section is : <math> \frac{d\sigma}{d\Omega} = \frac{R^2}{4}, </math> and the total cross section is : <math> \sigma_\text{tot} = \pi \left(r + R\right)^2. </math> In other words, the total scattering cross section is equal to the area of the circle (with radius {{math|''r'' + ''R''}}) within which the center of mass of the incoming sphere has to arrive for it to be deflected.
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