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Differential operator
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===Relation to commutative algebra=== {{Main Article|Differential calculus over commutative algebras}} An equivalent, but purely algebraic description of linear differential operators is as follows: an '''R'''-linear map ''P'' is a ''k''th-order linear differential operator, if for any ''k'' + 1 smooth functions <math>f_0,\ldots,f_k \in C^\infty(M)</math> we have :<math>[f_k,[f_{k-1},[\cdots[f_0,P]\cdots]]=0.</math> Here the bracket <math>[f,P]:\Gamma(E)\to \Gamma(F)</math> is defined as the commutator :<math>[f,P](s)=P(f\cdot s)-f\cdot P(s).</math> This characterization of linear differential operators shows that they are particular mappings between [[module (mathematics)|modules]] over a [[commutative algebra (structure)|commutative algebra]], allowing the concept to be seen as a part of [[commutative algebra]].
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