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Invertible matrix
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==== Inversion of 2 × 2 matrices ==== The ''cofactor equation'' listed above yields the following result for {{nowrap|2 × 2}} matrices. Inversion of these matrices can be done as follows:<ref>{{cite book |title=Introduction to linear algebra |edition=3rd |first1=Gilbert |last1=Strang |publisher=SIAM |year=2003 |isbn=978-0-9614088-9-3 |page=71 |url=https://books.google.com/books?id=Gv4pCVyoUVYC }}, [https://books.google.com/books?id=Gv4pCVyoUVYC&pg=PA71 Chapter 2, page 71] </ref> : <math>\mathbf{A}^{-1} = \begin{bmatrix} a & b \\ c & d \\ \end{bmatrix}^{-1} = \frac{1}{\det \mathbf{A}} \begin{bmatrix} \,\,\,d & \!\!-b \\ -c & \,a \\ \end{bmatrix} = \frac{1}{ad - bc} \begin{bmatrix} \,\,\,d & \!\!-b \\ -c & \,a \\ \end{bmatrix}. </math> This is possible because {{math|1/(''ad'' − ''bc'')}} is the [[reciprocal (mathematics)|reciprocal]] of the determinant of the matrix in question, and the same strategy could be used for other matrix sizes. The Cayley–Hamilton method gives : <math>\mathbf{A}^{-1} = \frac{1}{\det \mathbf{A}} \left[ \left( \operatorname{tr}\mathbf{A} \right) \mathbf{I} - \mathbf{A} \right] .</math>
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