Open main menu
Home
Random
Recent changes
Special pages
Community portal
Preferences
About Wikipedia
Disclaimers
Incubator escapee wiki
Search
User menu
Talk
Dark mode
Contributions
Create account
Log in
Editing
Quaternion
(section)
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
== Quaternions as pairs of complex numbers == {{Main|Cayley–Dickson construction}} Quaternions can be represented as pairs of complex numbers. From this perspective, quaternions are the result of applying the [[Cayley–Dickson construction]] to the complex numbers. This is a generalization of the construction of the complex numbers as pairs of real numbers. Let <math>\mathbb C^2</math> be a two-dimensional vector space over the complex numbers. Choose a basis consisting of two elements {{math|1}} and {{math|'''j'''}}. A vector in <math>\mathbb C^2</math> can be written in terms of the basis elements {{math|1}} and {{math|'''j'''}} as <math display=block>(a + b i)1 + (c + d i)\mathbf j. </math> If we define {{math|1='''j'''<sup>2</sup> = −1}} and {{math|1=''i'' '''j''' = −'''j''' ''i''}}, then we can multiply two vectors using the distributive law. Using {{math|'''k'''}} as an abbreviated notation for the product {{math|''i'' '''j'''}} leads to the same rules for multiplication as the usual quaternions. Therefore, the above vector of complex numbers corresponds to the quaternion {{math|''a'' + ''b i'' + ''c'' '''j''' + ''d'' '''k'''}}. If we write the elements of <math>\mathbb C^2</math> as ordered pairs and quaternions as quadruples, then the correspondence is <math display=block>(a + bi,\,c + di) \leftrightarrow (a,\,b,\,c,\,d).</math>
Edit summary
(Briefly describe your changes)
By publishing changes, you agree to the
Terms of Use
, and you irrevocably agree to release your contribution under the
CC BY-SA 4.0 License
and the
GFDL
. You agree that a hyperlink or URL is sufficient attribution under the Creative Commons license.
Cancel
Editing help
(opens in new window)