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System of linear equations
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===Elimination of variables=== The simplest method for solving a system of linear equations is to repeatedly eliminate variables. This method can be described as follows: # In the first equation, solve for one of the variables in terms of the others. # Substitute this expression into the remaining equations. This yields a system of equations with one fewer equation and unknown. # Repeat steps 1 and 2 until the system is reduced to a single linear equation. # Solve this equation, and then back-substitute until the entire solution is found. For example, consider the following system: : <math>\begin{cases} x+3y-2z=5\\ 3x+5y+6z=7\\ 2x+4y+3z=8 \end{cases}</math> Solving the first equation for ''x'' gives <math>x=5+2z-3y</math>, and plugging this into the second and third equation yields : <math>\begin{cases} y=3z+2\\ y=\tfrac{7}{2}z+1 \end{cases}</math> Since the LHS of both of these equations equal ''y'', equating the RHS of the equations. We now have: : <math>\begin{align} 3z+2=\tfrac{7}{2}z+1\\ \Rightarrow z=2 \end{align}</math> Substituting ''z'' = 2 into the second or third equation gives ''y'' = 8, and the values of ''y'' and ''z'' into the first equation yields ''x'' = β15. Therefore, the solution set is the ordered triple <math>(x,y,z)=(-15,8,2) </math>.
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