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Two knights endgame
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==Checkmate in problems== The possible checkmate on the edge of the board is the basis of some composed [[chess problem]]s, as well as variations of the checkmate with two knights against a pawn. ;Angos, 2005 {{Chess diagram small | tright | Angos, 2005 | | | |nl| | |kd| | |nd| |nl| | | | | | | | | | |kl| | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | White to move and mate in four }} In this problem by Alex Angos, White checkmates in four moves: :'''1. Ne6! Nd8''' :'''2. Nf6+ Kh8''' :'''3. Ng5 N'''β''any'' (Black is in [[zugzwang]] and any knight move must abandon the protection of the f7-square) :'''4. Nf7#'''<ref>{{Harvcol|Angos|2005|p=46}}</ref> {{clear}} ;;Berger, 1890 {{Chess diagram small | tright | Berger, 1890 | | | | |nd| |kd| | | | | | | | | | | | |nl|nl| |kl| | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | White to move and mate in four }} A similar problem was composed by [[Johann Berger]] in 1890. The solution is: :'''1. Nf7! Nd6''' :'''2. Nh6+ Kh8''' :'''3. Ng5''' followed by :'''4. Ngf7#'''.<ref>{{Harvcol|MatanoviΔ|1993|pp=492β93}}</ref> {{clear}} ;de Musset, 1849 {{Chess diagram small | tright | Alfred de Musset, 1849 | |nd| | |kd| |kl| | | | | | | | |rl | | | | | | | | | | | | |nl| | | | | | | | | |nl| | | | | | | | | | | | | | | | | | | | | | | | | | White to move and mate in three }} In this composition by [[Alfred de Musset]], White checkmates on the edge of the board in three moves with: :'''1. Rd7 Nxd7''' :'''2. Nc6 N'''β''any'' :'''3. Nf6#'''.<ref>{{Harvcol|Hooper|Whyld|1992}}</ref> {{clear}} ;Sobolevsky, 1951 {{Chess diagram | tright | P. Sobolevsky, [[Shakhmaty v SSSR]], 1951 | | | | | | | | | | | | | |kd| |nl | | | | | |bl|nl| | | | | | | | | | | | | | | | | | | | | | | | |kl | | | | | | |nd|bd | | | | | | | | | White to move and win }} In this [[Endgame study|study]] composed by Sobolevsky, White wins by checkmating with two knights: : '''1. Nh8+ Kg8''' : '''2. Kxg2 Bf4''' : '''3. Ng6 Bh6!''' : '''4. Ng5 Bg7!''' : '''5. Ne7+ Kh8''' : '''6. Nf7+ Kh7''' : '''7. Bh4! Bf6!''' : '''8. Ng5+ Kh6'''<ref>There is no apparent win after 8...Kg7, based on analysis by [[Houdini (chess)|Houdini 2.0]]. Yet according to [[Nalimov tablebases]] - White does win by force.</ref> : '''9. Ng8+ Kh5''' : '''10. Nxf6+! Kxh4''' : '''11. Nf3#'''<ref>{{Harvcol|Nunn|1981|p=6}}</ref> {{clear}} ;Nadanian, 2009 {{Chess diagram | tright | Ashot Nadanian, [[ChessBase]], 2009<ref>{{cite web|url=http://www.chessbase.com/puzzle/christmas2009/chr09-05.htm|title=ChessBase Christmas Puzzles: A tale of seven knights|date=2009-12-29|publisher=ChessBase|access-date=6 February 2010}} Broken link</ref> | | | | | | | |rl | | | |nd| | |rd| | | | |nl| | |nd|pd | | | | | | |kd|pl | | | |nl| |pd| | | | | | | | | |kl | | | | | | | | | | | | | | | | | White to move and win }} In this study composed by [[Ashot Nadanian]], White wins by checkmating with two knights: : '''1. Rg8!! Rxg8''' If 1...Re7, then 2.N6f5! Re1 3.Rxg6+ Kxh5 4.Rxh6+ Kg5 5.Nf3+ and White wins. : '''2. Ne4+ Kxh5''' : '''3. Ne6''' and checkmate on the next move, due to [[zugzwang]]; two white knights deliver four different checkmates:<ref>{{cite web|url=http://www.chessbase.com/puzzle/christmas2009/chr09-sol1.htm|title=Solutions to 2009 Christmas Puzzles|date=2010-02-02|publisher=ChessBase|access-date=6 February 2010|url-status=dead|archive-url=https://web.archive.org/web/20100206203021/http://www.chessbase.com/puzzle/christmas2009/chr09-sol1.htm|archive-date=6 February 2010}} Broken link</ref> * '''3... R'''β''any'' '''4. Ng7#''' * '''3... Nd'''β''any'' '''4. Nf6#''' * '''3... Ng'''β''any'' '''4. Nf4#''' * '''3... f3''' '''4. Ng3#''' {{clear}}
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