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Curvilinear coordinates
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===Christoffel symbols=== ;[[Christoffel symbols]] of the first kind <math>\Gamma_{kij}</math>: :<math> \mathbf{b}_{i,j} = \frac{\partial \mathbf{b}_i}{\partial q^j} = \mathbf{b}^k \Gamma_{kij} \quad \Rightarrow \quad \mathbf{b}_k \cdot \mathbf{b}_{i,j} = \Gamma_{kij} </math> where the comma denotes a [[partial derivative]] (see [[Ricci calculus]]). To express Ξ<sub>''kij''</sub> in terms of ''g<sub>ij</sub>'', :<math> \begin{align} g_{ij,k} & = (\mathbf{b}_i\cdot\mathbf{b}_j)_{,k} = \mathbf{b}_{i,k}\cdot\mathbf{b}_j + \mathbf{b}_i\cdot\mathbf{b}_{j,k} = \Gamma_{jik} + \Gamma_{ijk}\\ g_{ik,j} & = (\mathbf{b}_i\cdot\mathbf{b}_k)_{,j} = \mathbf{b}_{i,j}\cdot\mathbf{b}_k + \mathbf{b}_i\cdot\mathbf{b}_{k,j} = \Gamma_{kij} + \Gamma_{ikj}\\ g_{jk,i} & = (\mathbf{b}_j\cdot\mathbf{b}_k)_{,i} = \mathbf{b}_{j,i}\cdot\mathbf{b}_k + \mathbf{b}_j\cdot\mathbf{b}_{k,i} = \Gamma_{kji} + \Gamma_{jki} \end{align} </math> Since :<math>\mathbf{b}_{i,j} = \mathbf{b}_{j,i}\quad\Rightarrow\quad\Gamma_{kij} = \Gamma_{kji}</math> using these to rearrange the above relations gives :<math>\Gamma_{kij} = \frac{1}{2}(g_{ik,j} + g_{jk,i} - g_{ij,k}) = \frac{1}{2}[(\mathbf{b}_i\cdot\mathbf{b}_k)_{,j} + (\mathbf{b}_j\cdot\mathbf{b}_k)_{,i} - (\mathbf{b}_i\cdot\mathbf{b}_j)_{,k}] </math> ;[[Christoffel symbols]] of the second kind <math>\Gamma^k{}_{ji}</math>: :<math>\Gamma^k{}_{ij} = g^{kl}\Gamma_{lij} = \Gamma^k{}_{ji},\quad \cfrac{\partial \mathbf{b}_i}{\partial q^j} = \mathbf{b}_k \Gamma^k{}_{ij} </math> This implies that :<math> \Gamma^k{}_{ij} = \cfrac{\partial \mathbf{b}_i}{\partial q^j}\cdot\mathbf{b}^k = -\mathbf{b}_i\cdot\cfrac{\partial \mathbf{b}^k}{\partial q^j}\quad </math> since <math> \quad\cfrac{\partial}{\partial q^j}(\mathbf{b}_i\cdot\mathbf{b}^k)=0</math>. Other relations that follow are :<math> \cfrac{\partial \mathbf{b}^i}{\partial q^j} = -\Gamma^i{}_{jk}\mathbf{b}^k,\quad \boldsymbol{\nabla}\mathbf{b}_i = \Gamma^k{}_{ij}\mathbf{b}_k\otimes\mathbf{b}^j,\quad \boldsymbol{\nabla}\mathbf{b}^i = -\Gamma^i{}_{jk}\mathbf{b}^k\otimes\mathbf{b}^j </math>
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