Open main menu
Home
Random
Recent changes
Special pages
Community portal
Preferences
About Wikipedia
Disclaimers
Incubator escapee wiki
Search
User menu
Talk
Dark mode
Contributions
Create account
Log in
Editing
Short-time Fourier transform
(section)
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
==== Constraint ==== a. <math>\Delta_t \Delta_f = \tfrac{1}{N}</math>, where <math>N</math> is an integer b. <math>N \geq 2Q+1</math> c. Nyquist criterion (avoiding the aliasing effect): :<math>\Delta_t < \frac{1}{2\Omega}</math>, <math>\Omega</math> is the bandwidth of <math>x(\tau) w(t-\tau)</math> d. Only for implementing the [[Rectangular mask short-time Fourier transform|rectangular-STFT]] Rectangular window imposes the constraint :<math>w((n - p)\Delta_t) = 1 </math> Substitution gives: :<math> \begin{align} X(n\Delta_t, m\Delta_f) &= \sum_{p=n-Q}^{n+Q} w((n - p)\Delta_t)&x(p\Delta_t) e^{-\frac{j2\pi pm}{N}}\Delta_t \\ &= \sum_{p=n-Q}^{n+Q} &x(p\Delta_t) e^{-\frac{j2\pi pm}{N}}\Delta_t \\ \end{align} </math> Change of variable {{math|''n''-1}} for {{math|''n''}}: :<math> X((n-1)\Delta_t, m\Delta_f) = \sum_{p=n-1-Q}^{n-1+Q} x(p\Delta_t) e^{-\frac{j2\pi pm}{N}}\Delta_t </math> Calculate <math>X(\min{n}\Delta_t, m\Delta_f)</math> by the ''N''-point FFT: :<math>X(n_0\Delta_t, m\Delta_f) = \Delta_t e^{\frac{j 2\pi(Q-n_0)m}{N}} \sum_{q=0}^{N-1} x_1(q) e^{-j\frac{2\pi qm}{N}}, \qquad n_0=\min{(n)}</math> where :<math> x_1(q) = \begin{cases} x((n - Q + q)\Delta_t) & q \leq 2Q\\ 0 & q >2Q \end{cases}</math> Applying the recursive formula to calculate <math>X(n\Delta_t, m\Delta_f)</math> :<math>X(n\Delta_t, m\Delta_f) = X((n-1)\Delta_t, m\Delta_f) - x((n - Q -1)\Delta_t) e^{-\frac{j 2\pi(n-Q-1)m}{N}}\Delta_t + x((n+Q)\Delta_t)e^{-\frac{j 2\pi(n+Q)m}{N}}\Delta_t</math>
Edit summary
(Briefly describe your changes)
By publishing changes, you agree to the
Terms of Use
, and you irrevocably agree to release your contribution under the
CC BY-SA 4.0 License
and the
GFDL
. You agree that a hyperlink or URL is sufficient attribution under the Creative Commons license.
Cancel
Editing help
(opens in new window)