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Sufficient statistic
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==Other types of sufficiency== ===Bayesian sufficiency=== An alternative formulation of the condition that a statistic be sufficient, set in a Bayesian context, involves the posterior distributions obtained by using the full data-set and by using only a statistic. Thus the requirement is that, for almost every ''x'', :<math>\Pr(\theta\mid X=x) = \Pr(\theta\mid T(X)=t(x)). </math> More generally, without assuming a parametric model, we can say that the statistics ''T'' is ''predictive sufficient'' if :<math>\Pr(X'=x'\mid X=x) = \Pr(X'=x'\mid T(X)=t(x)).</math> It turns out that this "Bayesian sufficiency" is a consequence of the formulation above,<ref>{{cite book |last1=Bernardo |first1=J.M. |author-link1=JosΓ©-Miguel Bernardo |last2=Smith |first2=A.F.M. |author-link2=Adrian Smith (academic) |year=1994 |title=Bayesian Theory |publisher=Wiley |isbn=0-471-92416-4 |chapter=Section 5.1.4 }}</ref> however they are not directly equivalent in the infinite-dimensional case.<ref>{{cite journal |last1=Blackwell |first1=D. |author-link1=David Blackwell |last2=Ramamoorthi |first2=R. V. |title=A Bayes but not classically sufficient statistic. |journal=[[Annals of Statistics]] |volume=10 |year=1982 |issue=3 |pages=1025β1026 |doi=10.1214/aos/1176345895 |mr=663456 | zbl = 0485.62004 |doi-access=free }}</ref> A range of theoretical results for sufficiency in a Bayesian context is available.<ref>{{cite journal |last1=Nogales |first1=A.G. |last2=Oyola |first2=J.A. |last3=Perez |first3=P. |year=2000 |title=On conditional independence and the relationship between sufficiency and invariance under the Bayesian point of view |journal=Statistics & Probability Letters |volume=46 |issue=1 |pages=75β84 |doi=10.1016/S0167-7152(99)00089-9 |mr=1731351 | zbl = 0964.62003 |url=https://dialnet.unirioja.es/servlet/oaiart?codigo=118597 |url-access=subscription}}</ref> ===Linear sufficiency=== A concept called "linear sufficiency" can be formulated in a Bayesian context,<ref>{{cite journal |first1=M. |last1=Goldstein |first2=A. |last2=O'Hagan |year=1996 |title=Bayes Linear Sufficiency and Systems of Expert Posterior Assessments |journal=[[Journal of the Royal Statistical Society]] |series=Series B |volume=58 |issue=2 |pages=301β316 |doi=10.1111/j.2517-6161.1996.tb02083.x |jstor=2345978 }}</ref> and more generally.<ref>{{cite journal |last=Godambe |first=V. P. |year=1966 |title=A New Approach to Sampling from Finite Populations. II Distribution-Free Sufficiency |journal=[[Journal of the Royal Statistical Society]] |series=Series B |volume=28 |issue=2 |pages=320β328 |doi=10.1111/j.2517-6161.1966.tb00645.x |jstor=2984375 }}</ref> First define the best linear predictor of a vector ''Y'' based on ''X'' as <math>\hat E[Y\mid X]</math>. Then a linear statistic ''T''(''x'') is linear sufficient<ref>{{cite journal |last=Witting |first=T. |year=1987 |title=The linear Markov property in credibility theory |journal=ASTIN Bulletin |volume=17 |issue=1 |pages=71β84 |doi= 10.2143/ast.17.1.2014984|doi-access=free |hdl=20.500.11850/422507 |hdl-access=free }}</ref> if :<math>\hat E[\theta\mid X]= \hat E[\theta\mid T(X)] . </math>
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