Editing D'Hondt method (section)

==Procedure==
After all the votes have been tallied, successive [[quotient]]s are calculated for each party. The party with the largest quotient wins one seat, and its quotient is recalculated. This is repeated until the required number of seats is filled.  The formula for the quotient is<ref name="lijphart">{{citation|contribution=Degrees of proportionality of proportional representation formulas|first=Arend|last=Lijphart|author-link=Arend Lijphart|pages=170–179|title=Electoral Laws and Their Political Consequences|volume=1|series=Agathon series on representation|editor1-first=Bernard|editor1-last=Grofman|editor2-first=Arend|editor2-last=Lijphart|publisher=Algora Publishing|year=2003|isbn=9780875862675}}. See in particular the section "Sainte-Lague", [https://books.google.com/books?id=o1dqas0m8kIC&pg=PA174 pp. 174–175].</ref><ref name="gallagher"/>

<math display="block">\text{quot} = \frac{V}{s+1}</math>

where:
* {{mvar|V}} is the total number of votes that party received, and
* {{mvar|s}} is the number of seats that party has been allocated so far, initially 0 for all parties.

The total votes cast for each party in the electoral district is divided, first by 1, then by 2, then 3, up to the total number of seats to be allocated for the district/constituency. Say there are {{mvar|p}} parties and {{mvar|s}} seats. Then a grid of numbers can be created, with {{mvar|p}} rows and {{mvar|s}} columns, where the entry in the {{mvar|i}}th row and {{mvar|j}}th column is the number of votes won by the {{mvar|i}}th party, divided by {{mvar|j}}. The {{mvar|s}} winning entries are the {{mvar|s}} highest numbers in the whole grid; each party is given as many seats as there are winning entries in its row.

Alternatively, the procedure can be reversed by starting with a house apportionment that assigns "too many seats" to every party, then removing legislators one at a time from the most-overrepresented party.