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Inverse function theorem
(section)
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==Example== Consider the [[vector-valued function]] <math>F:\mathbb{R}^2\to\mathbb{R}^2\!</math> defined by: :<math> F(x,y)= \begin{bmatrix} {e^x \cos y}\\ {e^x \sin y}\\ \end{bmatrix}. </math> The Jacobian matrix of it at <math>(x, y)</math> is: :<math> JF(x,y)= \begin{bmatrix} {e^x \cos y} & {-e^x \sin y}\\ {e^x \sin y} & {e^x \cos y}\\ \end{bmatrix} </math> with the determinant: :<math> \det JF(x,y)= e^{2x} \cos^2 y + e^{2x} \sin^2 y= e^{2x}. \,\!</math> The determinant <math>e^{2x}\!</math> is nonzero everywhere. Thus the theorem guarantees that, for every point {{Mvar|p}} in <math>\mathbb{R}^2\!</math>, there exists a neighborhood about {{Mvar|p}} over which {{Mvar|F}} is invertible. This does not mean {{Mvar|F}} is invertible over its entire domain: in this case {{Mvar|F}} is not even [[injective]] since it is periodic: <math>F(x,y)=F(x,y+2\pi)\!</math>.
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