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Mercer's theorem
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== Details == We now explain in greater detail the structure of the proof of Mercer's theorem, particularly how it relates to [[spectral theory of compact operators]]. * The map ''K'' β¦ ''T''<sub>''K''</sub> is [[Injective function|injective]]. * ''T''<sub>''K''</sub> is a non-negative symmetric compact operator on ''L''<sup>2</sup>[''a'',''b'']; moreover ''K''(''x'', ''x'') ≥ 0. To show compactness, show that the image of the [[unit ball]] of ''L''<sup>2</sup>[''a'',''b''] under ''T''<sub>''K''</sub> is [[equicontinuous]] and apply [[Ascoli's theorem]], to show that the image of the unit ball is relatively compact in C([''a'',''b'']) with the [[uniform norm]] and ''a fortiori'' in ''L''<sup>2</sup>[''a'',''b'']. Now apply the [[spectral theorem]] for compact operators on Hilbert spaces to ''T''<sub>''K''</sub> to show the existence of the orthonormal basis {''e''<sub>i</sub>}<sub>i</sub> of ''L''<sup>2</sup>[''a'',''b''] :<math> \lambda_i e_i(t)= [T_K e_i](t) = \int_a^b K(t,s) e_i(s)\, ds. </math> If λ<sub>i</sub> ≠ 0, the eigenvector ([[eigenfunction]]) ''e''<sub>i</sub> is seen to be continuous on [''a'',''b'']. Now :<math> \sum_{i=1}^\infty \lambda_i |e_i(t) e_i(s)| \leq \sup_{x \in [a,b]} |K(x,x)|, </math> which shows that the sequence :<math> \sum_{i=1}^\infty \lambda_i e_i(t) e_i(s) </math> converges absolutely and uniformly to a kernel ''K''<sub>0</sub> which is easily seen to define the same operator as the kernel ''K''. Hence ''K''=''K''<sub>0</sub> from which Mercer's theorem follows. Finally, to show non-negativity of the eigenvalues one can write <math>\lambda \langle f,f \rangle= \langle f, T_{K}f \rangle</math> and expressing the right hand side as an integral well-approximated by its Riemann sums, which are non-negative by positive-definiteness of ''K'', implying <math>\lambda \langle f,f \rangle \geq 0</math>, implying <math>\lambda \geq 0 </math>.
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