Open main menu
Home
Random
Recent changes
Special pages
Community portal
Preferences
About Wikipedia
Disclaimers
Incubator escapee wiki
Search
User menu
Talk
Dark mode
Contributions
Create account
Log in
Editing
Residue (complex analysis)
(section)
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
== Contour integration<!-- Section needs introduction --> == {{See also|Contour integration}} === Contour integral of a monomial === Computing the residue of a [[monomial]] :<math>\oint_C z^k \, dz</math> makes most residue computations easy to do. Since path integral computations are [[homotopy]] invariant, we will let <math>C</math> be the circle with radius <math>1</math> going counter clockwise. Then, using the change of coordinates <math>z \to e^{i\theta}</math> we find that : <math>dz \to d(e^{i\theta}) = ie^{i\theta} \, d\theta</math> hence our integral now reads as :<math> \oint_C z^k dz = \int_0^{2\pi} i e^{i(k+1)\theta} \, d\theta = \begin{cases} 2\pi i & \text{if } k = -1, \\ 0 & \text{otherwise}. \end{cases} </math> Thus, the residue of <math>z^k</math> is 1 if integer <math>k=-1</math> and 0 otherwise. === Generalization to Laurent series === If a function is expressed as a [[Laurent series]] expansion around c as follows:<math display="block">f(z) = \sum_{n=-\infty}^\infty a_n(z-c)^n.</math>Then, the residue at the point c is calculated as:<math display="block">\operatorname{Res}(f,c) = {1 \over 2\pi i} \oint_\gamma f(z)\,dz = {1 \over 2\pi i} \sum_{n=-\infty}^\infty \oint_\gamma a_n(z-c)^n \,dz = a_{-1} </math>using the results from contour integral of a monomial for counter clockwise contour integral <math>\gamma</math> around a point c. Hence, if a [[Laurent series]] representation of a function exists around c, then its residue around c is known by the coefficient of the <math>(z-c)^{-1}</math> term. === Application in residue theorem === {{Main|Residue theorem}} For a [[meromorphic function]] <math>f</math>, with a finite set of singularities within a [[Curve orientation|positively oriented]] [[Jordan curve|simple closed curve]] <math>C</math> which does not pass through any singularity, the value of the contour integral is given according to [[residue theorem]], as:<math display="block"> \oint_C f(z)\, dz = 2\pi i \sum_{k=1}^n \operatorname{I}(C, a_k) \operatorname{Res}(f, a_k). </math>where <math>\operatorname{I}(C, a_k)</math>, the winding number, is <math>1</math> if <math>a_k</math> is in the interior of <math>C</math> and <math>0</math> if not, simplifying to:<math display="block"> \oint_\gamma f(z)\, dz = 2\pi i \sum \operatorname{Res}(f, a_k) </math>where <math>a_k</math> are all isolated singularities within the contour <math>C</math>.
Edit summary
(Briefly describe your changes)
By publishing changes, you agree to the
Terms of Use
, and you irrevocably agree to release your contribution under the
CC BY-SA 4.0 License
and the
GFDL
. You agree that a hyperlink or URL is sufficient attribution under the Creative Commons license.
Cancel
Editing help
(opens in new window)