Open main menu
Home
Random
Recent changes
Special pages
Community portal
Preferences
About Wikipedia
Disclaimers
Incubator escapee wiki
Search
User menu
Talk
Dark mode
Contributions
Create account
Log in
Editing
Rotational transition
(section)
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
=== Nuclear wave function === Quantum theoretical analysis of a molecule is simplified by use of [[Born–Oppenheimer approximation]]. Typically, rotational energies of molecules are smaller than [[molecular electronic transition|electronic transition]] energies by a factor of {{math|''m''/''M''}} ≈ 10<sup>−3</sup>–10<sup>−5</sup>, where {{math|''m''}} is electronic mass and {{math|''M''}} is typical nuclear mass.<ref>Chapter 10, ''Physics of Atoms and Molecules'', B.H. Bransden and C.J. Jochain, Pearson education, 2nd edition.</ref> From [[uncertainty principle]], period of motion is of the order of the [[Planck constant]] {{math|''h''}} divided by its energy. Hence nuclear rotational periods are much longer than the electronic periods. So electronic and nuclear motions can be treated separately. In the simple case of a diatomic molecule, the radial part of the [[Schrödinger Equation]] for a nuclear wave function {{math|''F''<sub>''s''</sub>('''R''')}}, in an electronic state {{math|''s''}}, is written as (neglecting spin interactions) <math display="block">\left[- \frac{\hbar^2}{2\mu R^2} \frac{\partial}{\partial R} \left(R^2 \frac{\partial}{\partial R}\right)+ \frac{\langle \Phi_s|N^2|\Phi_s \rangle}{2\mu R^2}+ E_s(R)-E\right]F_s(\mathbf R) = 0 </math> where {{math|''μ''}} is [[reduced mass]] of two nuclei, {{math|'''R'''}} is vector joining the two nuclei, {{math|''E''<sub>''s''</sub>(''R'')}} is energy [[eigenvalue]] of electronic wave function {{math|Φ<sub>''s''</sub>}} representing electronic state {{math|''s''}} and {{math|''N''}} is orbital [[momentum operator]] for the relative motion of the two nuclei given by <math display="block"> N^2 = -\hbar^2 \left[ \frac{1}{\sin\Theta} \frac{\partial}{\partial \Theta}\left(\sin \Theta \frac{\partial}{\partial \Theta}\right)+ \frac{1}{\sin^2\Theta} \frac{\partial^2}{\partial \Phi^2} \right] </math> The total [[wave function]] for the molecule is <math display="block"> \Psi_s = F_s(\mathbf R)\Phi_s(\mathbf R,\mathbf r_1, \mathbf r_2, \dots, \mathbf r_N)</math> where {{math|'''r'''<sub>''i''</sub>}} are position vectors from center of mass of molecule to {{math|''i''}}th electron. As a consequence of the Born-Oppenheimer approximation, the electronic wave functions {{math|Φ<sub>s</sub>}} is considered to vary very slowly with {{math|'''R'''}}. Thus the Schrödinger equation for an electronic wave function is first solved to obtain {{math|''E''<sub>''s''</sub>(''R'')}} for different values of {{math|''R''}}. {{math|''E''<sub>''s''</sub>}} then plays role of a [[potential well]] in analysis of nuclear wave functions {{math|''F''<sub>''s''</sub>('''R''')}}. [[File:Angular Momentum of a Diatomic Molecule.png|thumb|Vector addition triangle for orbital angular momentum of a diatomic molecule with components of orbital angular momentum of nuclei and orbital angular momentum of electrons, neglecting coupling between electron and nuclear orbital motion and spin-dependent coupling.Since angular momentum {{math|'''N'''}} of nuclei is perpendicular to internuclear vector {{math|'''R'''}}, components of electronic angular momentum {{math|'''L'''}} and total angular momentum {{math|'''J'''}} along {{math|'''R'''}} are equal.]]
Edit summary
(Briefly describe your changes)
By publishing changes, you agree to the
Terms of Use
, and you irrevocably agree to release your contribution under the
CC BY-SA 4.0 License
and the
GFDL
. You agree that a hyperlink or URL is sufficient attribution under the Creative Commons license.
Cancel
Editing help
(opens in new window)