Editing Truncated icosidodecahedron (section)

==Area and volume==
The surface area ''A'' and the volume ''V'' of the truncated icosidodecahedron of edge length ''a'' are:{{citation needed|date=January 2017}}
<!-- wrong value, given on MathWorld, need a source for correct value above
<math>\begin{align} A & = 30 \left [ 1 + \sqrt{ 2 \left ( 4 + \sqrt{5} + \sqrt{15+6\sqrt{6}} \right ) } \right ] a^2 \\
& \approx 175.031\,045a^2 \\-->
: <math>\begin{align} A &= 30 \left (1 + \sqrt{3} + \sqrt{5 + 2\sqrt{5}} \right)a^2 &&\approx 174.292\,0303a^2. \\ V &= \left( 95 + 50\sqrt{5} \right) a^3 &&\approx 206.803\,399a^3. \end{align}</math>

If a set of all 13 [[Archimedean solid]]s were constructed with all edge lengths equal, the truncated icosidodecahedron would be the largest.