Open main menu
Home
Random
Recent changes
Special pages
Community portal
Preferences
About Wikipedia
Disclaimers
Incubator escapee wiki
Search
User menu
Talk
Dark mode
Contributions
Create account
Log in
Editing
Waveplate
(section)
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
== Plate types == === Half-wave plate === [[File:Waveplate notext.png|thumb|right|A wave passing through a half-wave plate]] For a half-wave plate, the relationship between ''L'', Δ''n'', and λ<sub>0</sub> is chosen so that the phase shift between polarization components is Γ = π. Now suppose a linearly polarized wave with polarization vector <math>\mathbf{\hat p}</math> is incident on the crystal. Let θ denote the angle between <math>\mathbf{\hat p}</math> and <math>\mathbf{\hat f}</math>, where <math>\mathbf{\hat f}</math> is the vector along the waveplate's fast axis. Let ''z'' denote the propagation axis of the wave. The electric field of the incident wave is <math display="block">\mathbf{E}\,\mathrm{e}^{i(kz-\omega t)} = E\, \mathbf{\hat p}\,\mathrm{e}^{i(kz-\omega t)} = E (\cos\theta\, \mathbf{\hat f} + \sin\theta\, \mathbf{\hat s}) \mathrm{e}^{i(kz-\omega t)},</math> where <math>\mathbf{\hat s}</math> lies along the waveplate's slow axis. The effect of the half-wave plate is to introduce a phase shift term e<sup>''i''Γ</sup> = e<sup>''i''π</sup> = −1 between the ''f'' and ''s'' components of the wave, so that upon exiting the crystal the wave is now given by <math display="block">E (\cos\theta\, \mathbf{\hat f} - \sin\theta\, \mathbf{\hat s}) \mathrm{e}^{i(kz-\omega t)} = E [\cos(-\theta) \mathbf{\hat f} + \sin(-\theta) \mathbf{\hat s}] \mathrm{e}^{i(kz-\omega t)}.</math> If <math>\mathbf{\hat p}'</math> denotes the polarization vector of the wave exiting the waveplate, then this expression shows that the angle between <math>\mathbf{\hat p}'</math> and <math>\mathbf{\hat f}</math> is −θ. Evidently, the effect of the half-wave plate is to mirror the wave's polarization vector through the plane formed by the vectors <math>\mathbf{\hat f}</math> and <math>\mathbf{\hat z}</math>. For linearly polarized light, this is equivalent to saying that the effect of the half-wave plate is to rotate the polarization vector through an angle 2θ; however, for elliptically polarized light the half-wave plate also has the effect of inverting the light's [[chirality|handedness]].<ref name="hecht" /> === Quarter-wave plate === [[File:Circular.Polarization.Circularly.Polarized.Light And.Linearly.Polarized.Light.Comparison.svg|thumb|right|Two waves differing by a quarter-phase shift for one axis]] [[File:Circular.Polarization.Circularly.Polarized.Light Circular.Polarizer Creating.Left.Handed.Helix.View.svg|thumb|right|Creating circular polarization using a quarter-wave plate and a polarizing filter]] For a quarter-wave plate, the relationship between ''L'', Δ''n'', and λ<sub>0</sub> is chosen so that the phase shift between polarization components is Γ = π/2. Now suppose a linearly polarized wave is incident on the crystal. This wave can be written as :<math>(E_f \mathbf{\hat f} + E_s \mathbf{\hat s})\mathrm{e}^{i(kz-\omega t)},</math> where the ''f'' and ''s'' axes are the quarter-wave plate's fast and slow axes, respectively, the wave propagates along the ''z'' axis, and ''E<sub>f</sub>'' and ''E<sub>s</sub>'' are real. The effect of the quarter-wave plate is to introduce a phase shift term e<sup>''i''Γ</sup> =e<sup>''i''π/2</sup> = ''i'' between the ''f'' and ''s'' components of the wave, so that upon exiting the crystal the wave is now given by :<math>(E_f \mathbf{\hat f} + i E_s \mathbf{\hat s})\mathrm{e}^{i(kz-\omega t)}.</math> The wave is now elliptically polarized. If the axis of polarization of the incident wave is chosen so that it makes a 45° with the fast and slow axes of the waveplate, then ''E<sub>f</sub>'' = ''E<sub>s</sub>'' ≡ ''E'', and the resulting wave upon exiting the waveplate is :<math>E(\mathbf{\hat f}+i\mathbf{\hat s})\mathrm{e}^{i(kz-\omega t)},</math> and the wave is circularly polarized. If the axis of polarization of the incident wave is chosen so that it makes a 0° with the fast or slow axes of the waveplate, then the polarization will not change, so remains linear. If the angle is in between 0° and 45° the resulting wave has an elliptical polarization. A circulating polarization can be visualized as the sum of two linear polarizations with a phase difference of 90°. The output depends on the polarization of the input. Suppose polarization axes x and y parallel with the slow and fast axis of the waveplate: [[File:Polaryzacja kołowa.gif|alt=Composition of two linearly polarized waves, phase shifted by π/2|thumb|Composition of two linearly polarized waves, phase shifted by π/2]] [[File:Quarter wave plate polarizaton.gif]] The polarization of the incoming photon (or beam) can be resolved as two polarizations on the x and y axis. If the input polarization is parallel to the fast or slow axis, then there is no polarization of the other axis, so the output polarization is the same as the input (only the phase more or less delayed). If the input polarization is 45° to the fast and slow axis, the polarization on those axes are equal. But the phase of the output of the slow axis will be delayed 90° with the output of the fast axis. If not the amplitude but both sine values are displayed, then x and y combined will describe a circle. With other angles than 0° or 45° the values in fast and slow axis will differ and their resultant output will describe an ellipse. === Full-wave, or sensitive-tint plate === A full-wave plate introduces a phase difference of exactly one wavelength between the two polarization directions, for one wavelength of light. In [[optical mineralogy]], it is common to use a full-wave plate designed for green light (a wavelength near 540 nm). Linearly polarized white light which passes through the plate becomes elliptically polarized, except for that green light wavelength, which will remain linear. If a linear polarizer oriented perpendicular to the original polarization is added, this green wavelength is fully extinguished but elements of the other colors remain. This means that under these conditions the plate will appear an intense shade of red-violet, sometimes known as "sensitive tint".<ref>{{cite web |url=http://www.doitpoms.ac.uk/tlplib/optical-microscopy/plates.php |title=Tint plates |website=DoITPoMS |publisher=University of Cambridge |access-date=Dec 31, 2016}}</ref> This gives rise to this plate's alternative names, the ''sensitive-tint plate'' or (less commonly) ''red-tint plate''. These plates are widely used in mineralogy to aid in identification of [[mineral]]s in [[thin section]]s of [[rock (geology)|rocks]].<ref name=Winchell121>{{cite book |last1=Winchell |first1=Newton Horace |first2=Alexander Newton |last2=Winchell |title=Elements of Optical Mineralogy: Principles and Methods |volume=1 |location=New York |publisher=John Wiley & Sons |year=1922 |page=121}}</ref> === Multiple-order vs. zero-order waveplates === A multiple-order waveplate is made from a single birefringent crystal that produces an integer multiple of the rated retardance (for example, a multiple-order half-wave plate may have an absolute retardance of 37λ/2). By contrast, a zero-order waveplate produces exactly the specified retardance. This can be accomplished by combining two multiple-order wave plates such that the difference in their retardances yields the net (true) retardance of the waveplate. Zero-order waveplates are less sensitive to temperature and wavelength shifts, but are more expensive than multiple-order ones.<ref>{{Cite web |url=https://www.edmundoptics.com/resources/application-notes/optics/understanding-waveplates/ |title=Understanding Waveplates |publisher=Edmund Optics |website=www.edmundoptics.com |access-date=2019-05-03}}</ref> Stacking a series of different-order waveplates with polarization filters between them yields a [[Lyot filter]]. Either the filters can be rotated, or the waveplates [[Liquid crystal tunable filter|can be replaced]] with [[liquid crystal]] layers, to obtain a widely tunable [[Band-pass filter|pass band]] in optical transmission spectrum.
Edit summary
(Briefly describe your changes)
By publishing changes, you agree to the
Terms of Use
, and you irrevocably agree to release your contribution under the
CC BY-SA 4.0 License
and the
GFDL
. You agree that a hyperlink or URL is sufficient attribution under the Creative Commons license.
Cancel
Editing help
(opens in new window)