Open main menu
Home
Random
Recent changes
Special pages
Community portal
Preferences
About Wikipedia
Disclaimers
Incubator escapee wiki
Search
User menu
Talk
Dark mode
Contributions
Create account
Log in
Editing
Well-defined expression
(section)
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
=="Definition" as anticipation of definition== In order to avoid the quotation marks around "define" in the previous simple example, the "definition" of <math>f</math> could be broken down into two logical steps: {{ordered list | ''The definition'' of the [[binary relation]]. In the example: :<math>f := \bigl\{(a,i) \mid i \in \{0,1\} \wedge a \in A_i \bigr\}, </math> (which so far is nothing but a certain subset of the [[Cartesian product]] <math>A \times \{0,1\}</math>.) | ''The assertion''. The binary relation <math>f</math> is a function; in the example: :<math>f: A \rightarrow \{0,1\}.</math> }} While the definition in step 1 is formulated with the freedom of any definition and is certainly effective (without the need to classify it as "well defined"), the assertion in step 2 has to be proven. That is, <math>f</math> is a function if and only if <math>A_0 \cap A_1 = \emptyset</math>, in which case <math>f</math> β as a function β is well defined. On the other hand, if <math>A_0 \cap A_1 \neq \emptyset</math>, then for an <math>a \in A_0 \cap A_1</math>, we would have that <math>(a,0) \in f</math> ''and'' <math>(a,1) \in f</math>, which makes the binary relation <math>f</math> not ''functional'' (as defined in [[Binary relation#Special types of binary relations]]) and thus not well defined as a function. Colloquially, the "function" <math>f</math> is also called ambiguous at point <math>a</math> (although there is ''per definitionem'' never an "ambiguous function"), and the original "definition" is pointless. <br> <br /> Despite these subtle logical problems, it is quite common to use the term definition (without apostrophes) for "definitions" of this kind, for three reasons: # It provides a handy shorthand of the two-step approach. # The relevant mathematical reasoning (i.e., step 2) is the same in both cases. # In mathematical texts, the assertion is "up to 100%" true.
Edit summary
(Briefly describe your changes)
By publishing changes, you agree to the
Terms of Use
, and you irrevocably agree to release your contribution under the
CC BY-SA 4.0 License
and the
GFDL
. You agree that a hyperlink or URL is sufficient attribution under the Creative Commons license.
Cancel
Editing help
(opens in new window)