Open main menu
Home
Random
Recent changes
Special pages
Community portal
Preferences
About Wikipedia
Disclaimers
Incubator escapee wiki
Search
User menu
Talk
Dark mode
Contributions
Create account
Log in
Editing
Whitehead problem
(section)
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
==Shelah's proof== Saharon Shelah showed that, given the canonical [[ZFC]] axiom system, the problem is [[Independence (mathematical logic)|independent of the usual axioms of set theory]].{{r|Shelah1974}} More precisely, he showed that: * If [[Axiom of constructibility|every set is constructible]], then every Whitehead group is free; * If [[Martin's axiom]] and the negation of the [[continuum hypothesis]] both hold, then there is a non-free Whitehead group. Since the [[consistency]] of ZFC implies the consistency of both of the following: *The axiom of constructibility (which asserts that all sets are constructible); *Martin's axiom plus the negation of the continuum hypothesis, Whitehead's problem cannot be resolved in ZFC.
Edit summary
(Briefly describe your changes)
By publishing changes, you agree to the
Terms of Use
, and you irrevocably agree to release your contribution under the
CC BY-SA 4.0 License
and the
GFDL
. You agree that a hyperlink or URL is sufficient attribution under the Creative Commons license.
Cancel
Editing help
(opens in new window)