Editing HSL and HSV (section)

====HSI to RGB====
Given an HSI color with hue {{math|''H'' ∈ [0°, 360°)}}, saturation {{math|''S''<sub>''I''</sub> ∈ [0, 1]}}, and intensity {{math|''I'' ∈ [0, 1]}}, we can use the same strategy, in a slightly different order:
: <math>H^\prime = \frac{H}{60^\circ}</math>
: <math>Z = 1 - |H^\prime \;\bmod 2 - 1|</math>
: <math>C = \frac{3 \cdot I \cdot S_I}{1 + Z}</math>
: <math>X = C \cdot Z</math>

Where <math>C</math> is the chroma.

Then we can, again, find a point {{math|(''R''<sub>1</sub>, ''G''<sub>1</sub>, ''B''<sub>1</sub>)}} along the bottom three faces of the RGB cube, with the same hue and chroma as our color (using the intermediate value ''X'' for the second largest component of this color):
: <math>(R_1, G_1, B_1) = \begin{cases}
  (0, 0, 0) &\text{if } H \text{ is undefined} \\
  (C, X, 0) &\text{if } 0 \leq H^\prime \leq 1 \\
  (X, C, 0) &\text{if } 1 \leq H^\prime \leq 2 \\
  (0, C, X) &\text{if } 2 \leq H^\prime \leq 3 \\
  (0, X, C) &\text{if } 3 \leq H^\prime \leq 4 \\
  (X, 0, C) &\text{if } 4 \leq H^\prime \leq 5 \\
  (C, 0, X) &\text{if } 5 \leq H^\prime < 6
\end{cases}</math>

Overlap (when <math>H^\prime</math> is an integer) occurs because two ways to calculate the value are equivalent: <math>X = 0</math> or <math>X = C</math>, as appropriate.

Finally, we can find ''R'', ''G'', and ''B'' by adding the same amount to each component, to match lightness:
: <math>m = I \cdot (1 - S_I)</math>
: <math>(R, G, B) = (R_1 + m, G_1 + m, B_1 + m)</math>