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Invertible matrix
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=== By Neumann series === If a matrix {{math|'''A'''}} has the property that : <math>\lim_{n \to \infty} (\mathbf I - \mathbf A)^n = 0</math> then {{math|'''A'''}} is nonsingular and its inverse may be expressed by a [[Neumann series]]:<ref> {{cite book | last = Stewart | first = Gilbert | title = Matrix Algorithms: Basic decompositions | publisher = SIAM | year = 1998 | pages = 55 | isbn = 978-0-89871-414-2 }}</ref> : <math>\mathbf A^{-1} = \sum_{n = 0}^\infty (\mathbf I - \mathbf A)^n.</math> Truncating the sum results in an "approximate" inverse which may be useful as a [[preconditioner]]. Note that a truncated series can be accelerated exponentially by noting that the Neumann series is a [[geometric sum]]. As such, it satisfies : <math>\sum_{n=0}^{2^L-1} (\mathbf I - \mathbf A)^n = \prod_{l=0}^{L-1}\left(\mathbf I + (\mathbf I - \mathbf A)^{2^l}\right)</math>. Therefore, only {{math|2''L'' β 2}} matrix multiplications are needed to compute {{math|2{{sup|''L''}}}} terms of the sum. More generally, if {{math|'''A'''}} is "near" the invertible matrix {{math|'''X'''}} in the sense that : <math>\lim_{n \to \infty} \left(\mathbf I - \mathbf X^{-1} \mathbf A\right)^n = 0 \mathrm{~~or~~} \lim_{n \to \infty} \left(\mathbf I - \mathbf A \mathbf X^{-1}\right)^n = 0</math> then {{math|'''A'''}} is nonsingular and its inverse is : <math>\mathbf A^{-1} = \sum_{n = 0}^\infty \left(\mathbf X^{-1} (\mathbf X - \mathbf A)\right)^n \mathbf X^{-1}~.</math> If it is also the case that {{math|'''A''' β '''X'''}} has [[rank (linear algebra)|rank]] 1 then this simplifies to : <math>\mathbf A^{-1} = \mathbf X^{-1} - \frac{\mathbf X^{-1} (\mathbf A - \mathbf X) \mathbf X^{-1}}{1 + \operatorname{tr}\left(\mathbf X^{-1} (\mathbf A - \mathbf X)\right)}~.</math>
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