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Determinant
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=== Upper and lower bounds === For a positive definite matrix {{math|''A''}}, the trace operator gives the following tight lower and upper bounds on the log determinant :<math>\operatorname{tr}\left(I - A^{-1}\right) \le \log\det(A) \le \operatorname{tr}(A - I)</math> with equality if and only if {{math|1=''A'' = ''I''}}. This relationship can be derived via the formula for the [[Kullback-Leibler divergence]] between two [[multivariate normal]] distributions. Also, :<math>\frac{n}{\operatorname{tr}\left(A^{-1}\right)} \leq \det(A)^\frac{1}{n} \leq \frac{1}{n}\operatorname{tr}(A) \leq \sqrt{\frac{1}{n}\operatorname{tr}\left(A^2\right)}.</math> These inequalities can be proved by expressing the traces and the determinant in terms of the eigenvalues. As such, they represent the well-known fact that the [[harmonic mean]] is less than the [[geometric mean]], which is less than the [[arithmetic mean]], which is, in turn, less than the [[root mean square]].
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