Open main menu
Home
Random
Recent changes
Special pages
Community portal
Preferences
About Wikipedia
Disclaimers
Incubator escapee wiki
Search
User menu
Talk
Dark mode
Contributions
Create account
Log in
Editing
Path integral formulation
(section)
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
=== Schwinger–Dyson equations === {{Main|Schwinger–Dyson equation}} Since this formulation of quantum mechanics is analogous to classical action principle, one might expect that identities concerning the action in classical mechanics would have quantum counterparts derivable from a functional integral. This is often the case. In the language of functional analysis, we can write the [[Euler–Lagrange equation]]s as : <math>\frac{\delta \mathcal{S}[\varphi]}{\delta \varphi} = 0</math> (the left-hand side is a [[functional derivative]]; the equation means that the action is stationary under small changes in the field configuration). The quantum analogues of these equations are called the [[Schwinger–Dyson equation]]s. If the [[functional measure]] {{math|{{mathcal|D}}''ϕ''}} turns out to be [[Translational symmetry|translationally invariant]] (we'll assume this for the rest of this article, although this does not hold for, let's say [[nonlinear sigma model]]s), and if we assume that after a [[Wick rotation]] : <math>e^{i\mathcal{S}[\varphi]},</math> which now becomes : <math>e^{-H[\varphi]}</math> for some {{mvar|H}}, it goes to zero faster than a [[Multiplicative inverse|reciprocal]] of any [[polynomial]] for large values of {{mvar|φ}}, then we can [[integration by parts|integrate by parts]] (after a Wick rotation, followed by a Wick rotation back) to get the following Schwinger–Dyson equations for the expectation: : <math>\left\langle \frac{\delta F[\varphi]}{\delta \varphi} \right\rangle = -i \left\langle F[\varphi]\frac{\delta \mathcal{S}[\varphi]}{\delta\varphi} \right\rangle</math> for any polynomially-bounded functional {{mvar|F}}. In the [[deWitt notation]] this looks like<ref>{{cite journal |first=Jean |last=Zinn-Justin |date=2009 |title=Path integral |journal=Scholarpedia |volume=4 |issue=2 |doi=10.4249/scholarpedia.8674 |bibcode=2009SchpJ...4.8674Z |at=8674|doi-access=free }}</ref> : <math>\left\langle F_{,i} \right\rangle = -i \left\langle F \mathcal{S}_{,i} \right\rangle.</math> These equations are the analog of the [[on-shell]] EL equations. The time ordering is taken before the time derivatives inside the {{math|{{mathcal|S}}<sub>,''i''</sub>}}. If {{mvar|J}} (called the [[source field]]) is an element of the [[dual space]] of the field configurations (which has at least an [[affine structure]] because of the assumption of the [[translational invariance]] for the functional measure), then the [[generating functional]] {{mvar|Z}} of the source fields is '''defined''' to be : <math>Z[J] = \int \mathcal{D}\varphi e^{i\left(\mathcal{S}[\varphi] + \langle J,\varphi \rangle\right)}.</math> Note that : <math>\frac{\delta^n Z}{\delta J(x_1) \cdots \delta J(x_n)}[J] = i^n \, Z[J] \, \left\langle \varphi(x_1)\cdots \varphi(x_n)\right\rangle_J,</math> or : <math>Z^{,i_1\cdots i_n}[J] = i^n Z[J] \left \langle \varphi^{i_1}\cdots \varphi^{i_n}\right\rangle_J,</math> where : <math>\langle F \rangle_J = \frac{\int \mathcal{D}\varphi F[\varphi]e^{i\left(\mathcal{S}[\varphi] + \langle J,\varphi \rangle\right)}}{\int\mathcal{D}\varphi e^{i\left(\mathcal{S}[\varphi] + \langle J,\varphi \rangle\right)}}.</math> Basically, if {{math|{{mathcal|D}}''φ'' ''e''<sup>''i''{{mathcal|S}}[''φ'']</sup>}} is viewed as a functional distribution (this shouldn't be taken too literally as an interpretation of [[Quantum field theory|QFT]], unlike its Wick-rotated [[statistical mechanics]] analogue, because we have [[time ordering]] complications here!), then {{math|{{angbr|''φ''(''x''<sub>1</sub>) ... ''φ''(''x<sub>n</sub>'')}}}} are its [[moment (mathematics)|moments]], and {{mvar|Z}} is its [[Fourier transform]]. If {{mvar|F}} is a functional of {{mvar|φ}}, then for an [[Operator (mathematics)|operator]] {{mvar|K}}, {{math|''F''[''K'']}} is defined to be the operator that substitutes {{mvar|K}} for {{mvar|φ}}. For example, if : <math>F[\varphi] = \frac{\partial^{k_1}}{\partial x_1^{k_1}}\varphi(x_1)\cdots \frac{\partial^{k_n}}{\partial x_n^{k_n}}\varphi(x_n),</math> and {{mvar|G}} is a functional of {{mvar|J}}, then : <math>F\left[-i\frac{\delta}{\delta J}\right] G[J] = (-i)^n \frac{\partial^{k_1}}{\partial x_1^{k_1}}\frac{\delta}{\delta J(x_1)} \cdots \frac{\partial^{k_n}}{\partial x_n^{k_n}}\frac{\delta}{\delta J(x_n)} G[J].</math> Then, from the properties of the [[functional integral]]s : <math>\left \langle \frac{\delta \mathcal{S}}{\delta \varphi(x)} [\varphi] + J(x)\right\rangle_J = 0</math> we get the "master" Schwinger–Dyson equation: : <math>\frac{\delta \mathcal{S}}{\delta \varphi(x)}\left[-i \frac{\delta}{\delta J}\right]Z[J] + J(x)Z[J] = 0,</math> or : <math>\mathcal{S}_{,i}[-i\partial]Z + J_i Z = 0.</math> If the functional measure is not translationally invariant, it might be possible to express it as the product {{math|''M''[''φ''] {{mathcal|D}}''φ''}}, where {{mvar|M}} is a functional and {{math|{{mathcal|D}}''φ''}} is a translationally invariant measure. This is true, for example, for nonlinear sigma models where the [[target space]] is diffeomorphic to {{math|'''R'''<sup>''n''</sup>}}. However, if the [[target manifold]] is some topologically nontrivial space, the concept of a translation does not even make any sense. In that case, we would have to replace the {{mathcal|S}} in this equation by another functional : <math>\hat{\mathcal{S}} = \mathcal{S} - i\ln M.</math> If we expand this equation as a [[Taylor series]] about ''J'' {{=}} 0, we get the entire set of Schwinger–Dyson equations.
Edit summary
(Briefly describe your changes)
By publishing changes, you agree to the
Terms of Use
, and you irrevocably agree to release your contribution under the
CC BY-SA 4.0 License
and the
GFDL
. You agree that a hyperlink or URL is sufficient attribution under the Creative Commons license.
Cancel
Editing help
(opens in new window)