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Entropy (information theory)
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===Approximation to binomial coefficient=== For integers {{math|0 < ''k'' < ''n''}} let {{math|1=''q'' = ''k''/''n''}}. Then <math display="block">\frac{2^{n\Eta(q)}}{n+1} \leq \tbinom nk \leq 2^{n\Eta(q)},</math> where <ref>Aoki, New Approaches to Macroeconomic Modeling.</ref>{{rp|p=43}} <math display="block">\Eta(q) = -q \log_2(q) - (1-q) \log_2(1-q).</math> {| class="toccolours collapsible collapsed" width="80%" style="text-align:left; margin-1.5em;" !Proof (sketch) |- |Note that <math>\tbinom nk q^{qn}(1-q)^{n-nq}</math> is one term of the expression <math display="block">\sum_{i=0}^n \tbinom ni q^i(1-q)^{n-i} = (q + (1-q))^n = 1.</math> Rearranging gives the upper bound. For the lower bound one first shows, using some algebra, that it is the largest term in the summation. But then, <math display="block">\binom nk q^{qn}(1-q)^{n-nq} \geq \frac{1}{n+1}</math> since there are {{math|''n'' + 1}} terms in the summation. Rearranging gives the lower bound. |} A nice interpretation of this is that the number of binary strings of length {{math|''n''}} with exactly {{math|''k''}} many 1's is approximately <math>2^{n\Eta(k/n)}</math>.<ref>Probability and Computing, M. Mitzenmacher and E. Upfal, Cambridge University Press</ref>
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