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Electromagnetic four-potential
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== Gauge freedom == When [[Musical isomorphism|flattened]] to a [[one-form]] (in tensor notation, <math>A_\mu</math>), the four-potential <math>A</math> (normally written as a vector or, <math>A^\mu</math> in tensor notation) can be decomposed{{clarify|date=November 2022|reason=What are the operators? d is the four gradient, but what is delta. Which differential complex?}} via the [[Hodge theory|Hodge decomposition theorem]] as the sum of an [[Closed and exact differential forms|exact]], a coexact, and a harmonic form, : <math>A = d \alpha + \delta \beta + \gamma</math>. There is [[gauge freedom]] in {{math|''A''}} in that of the three forms in this decomposition, only the coexact form has any effect on the [[electromagnetic tensor]] : <math>F = d A</math>. Exact forms are closed, as are harmonic forms over an appropriate domain, so <math>d d \alpha = 0</math> and <math>d\gamma = 0</math>, always. So regardless of what <math>\alpha</math> and <math>\gamma</math> are, we are left with simply : <math>F = d \delta \beta</math>. In infinite flat Minkowski space, every closed form is exact. Therefore the <math>\gamma</math> term vanishes. Every gauge transform of <math>A</math> can thus be written as : <math>A \Rightarrow A + d\alpha</math>.
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