Open main menu
Home
Random
Recent changes
Special pages
Community portal
Preferences
About Wikipedia
Disclaimers
Incubator escapee wiki
Search
User menu
Talk
Dark mode
Contributions
Create account
Log in
Editing
Geometric series
(section)
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
== Connection to the power series == Like the geometric series, a [[power series]] has one parameter for a common variable raised to successive powers corresponding to the geometric series's <math> r </math>, but it has additional parameters <math>a_0, a_1, a_2, \ldots,</math> one for each term in the series, for the distinct coefficients of each <math>x^0, x^1, x^2, \ldots</math>, rather than just a single additional parameter <math>a</math> for all terms, the common coefficient of <math>r^k</math> in each term of a geometric series. The geometric series can therefore be considered a class of power series in which the sequence of coefficients satisfies <math>a_k = a</math> for all <math>k</math> and <math>x = r</math>.{{sfnp|Apostol|1967|pp=389}} This special class of power series plays an important role in mathematics, for instance for the study of [[ordinary generating functions]] in combinatorics and the [[Summation method|summation]] of divergent series in analysis. Many other power series can be written as transformations and combinations of geometric series, making the geometric series formula a convenient tool for calculating formulas for those power series as well.{{r|wilf|bo}} As a power series, the geometric series has a [[radius of convergence]] of 1.{{r|spivak}} This could be seen as a consequence of the [[Cauchy–Hadamard theorem]] and the fact that <math display="block">\lim_{n \rightarrow \infty}\sqrt[n]{a} = 1</math> for any <math>a</math> or as a consequence of the [[ratio test]] for the convergence of infinite series, with <math display="block">\lim_{n \rightarrow \infty} \frac{|a r^{n+1}| }{ |a r^{n}|} = |r|</math> implying convergence only for <math>|r| < 1.</math> However, both the ratio test and the Cauchy–Hadamard theorem are proven using the geometric series formula as a logically prior result, so such reasoning would be subtly circular.{{sfnp|Spivak|2008|p=476}}
Edit summary
(Briefly describe your changes)
By publishing changes, you agree to the
Terms of Use
, and you irrevocably agree to release your contribution under the
CC BY-SA 4.0 License
and the
GFDL
. You agree that a hyperlink or URL is sufficient attribution under the Creative Commons license.
Cancel
Editing help
(opens in new window)