Open main menu
Home
Random
Recent changes
Special pages
Community portal
Preferences
About Wikipedia
Disclaimers
Incubator escapee wiki
Search
User menu
Talk
Dark mode
Contributions
Create account
Log in
Editing
Interpretability logic
(section)
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
=== Logic TOL === The language of TOL extends that of classical propositional logic by adding the modal operator <math>\Diamond</math> which is allowed to take any nonempty sequence of arguments. The arithmetical interpretation of <math>\Diamond( p_1,\ldots,p_n)</math> is “<math>(PA+p_1,\ldots,PA+p_n)</math> is a [[tolerant sequence]] of theories”. Axioms (with <math>p,q</math> standing for any formulas, <math>\vec{r},\vec{s}</math> for any sequences of formulas, and <math>\Diamond()</math> identified with ⊤): # All classical tautologies # <math>\Diamond (\vec{r},p,\vec{s})\rightarrow \Diamond (\vec{r}, p\wedge\neg q,\vec{s})\vee \Diamond (\vec{r}, q,\vec{s}) </math> # <math>\Diamond (p)\rightarrow \Diamond (p\wedge \neg\Diamond (p)) </math> # <math>\Diamond (\vec{r},p,\vec{s})\rightarrow \Diamond (\vec{r},\vec{s})</math> # <math>\Diamond (\vec{r},p,\vec{s})\rightarrow \Diamond (\vec{r},p,p,\vec{s})</math> # <math>\Diamond (p,\Diamond(\vec{r}))\rightarrow \Diamond (p\wedge\Diamond(\vec{r}))</math> # <math>\Diamond (\vec{r},\Diamond(\vec{s}))\rightarrow \Diamond (\vec{r},\vec{s})</math> Rules of inference: # “From <math>p</math> and <math>p\rightarrow q</math> conclude <math>q</math>” # “From <math>\neg p</math> conclude <math>\neg \Diamond( p)</math>”. The completeness of TOL with respect to its arithmetical interpretation was proven by [[Giorgi Japaridze]].
Edit summary
(Briefly describe your changes)
By publishing changes, you agree to the
Terms of Use
, and you irrevocably agree to release your contribution under the
CC BY-SA 4.0 License
and the
GFDL
. You agree that a hyperlink or URL is sufficient attribution under the Creative Commons license.
Cancel
Editing help
(opens in new window)