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Lyapunov function
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== Basic Lyapunov theorems for autonomous systems== {{main article|Lyapunov stability}} Let <math>x^* = 0</math> be an equilibrium point of the autonomous system :<math>\dot{x} = f(x).</math> and use the notation <math>\dot{V}(x)</math> to denote the time derivative of the Lyapunov-candidate-function <math>V</math>: :<math>\dot{V}(x) = \frac{d}{dt} V(x(t)) = \frac{\partial V}{\partial x}\cdot \frac{dx}{dt} = \nabla V \cdot \dot{x} = \nabla V\cdot f(x).</math> ===Locally asymptotically stable equilibrium=== If the equilibrium point is isolated, the Lyapunov-candidate-function <math>V</math> is locally positive definite, and the time derivative of the Lyapunov-candidate-function is locally negative definite: :<math>\dot{V}(x) < 0 \quad \forall x \in \mathcal{B}(0)\setminus\{0\},</math> for some neighborhood <math>\mathcal{B}(0)</math> of origin, then the equilibrium is proven to be locally asymptotically stable. ===Stable equilibrium=== If <math>V</math> is a Lyapunov function, then the equilibrium is [[Lyapunov stable]]. ===Globally asymptotically stable equilibrium=== If the Lyapunov-candidate-function <math>V</math> is globally positive definite, [[Radially unbounded function|radially unbounded]], the equilibrium isolated and the time derivative of the Lyapunov-candidate-function is globally negative definite: :<math>\dot{V}(x) < 0 \quad \forall x \in \R ^n\setminus\{0\},</math> then the equilibrium is proven to be [[Stability theory|globally asymptotically stable]]. The Lyapunov-candidate function <math>V(x)</math> is radially unbounded if :<math>\| x \| \to \infty \Rightarrow V(x) \to \infty. </math> (This is also referred to as norm-coercivity.) The converse is also true,<ref name=Massera1949>{{Citation | author = Massera, José Luis | year = 1949 | title = On Liapounoff's conditions of stability | journal = Annals of Mathematics |series=Second Series | volume = 50 | issue = 3 | pages = 705–721 | doi = 10.2307/1969558 | mr = 0035354 | jstor = 1969558 }}</ref> and was proved by [[José Luis Massera]] (see also [[Massera's lemma]]).
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