Open main menu
Home
Random
Recent changes
Special pages
Community portal
Preferences
About Wikipedia
Disclaimers
Incubator escapee wiki
Search
User menu
Talk
Dark mode
Contributions
Create account
Log in
Editing
Polar decomposition
(section)
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
===Relation to the SVD=== In terms of the [[singular value decomposition]] (SVD) of <math>A</math>, <math>A = W\Sigma V^*</math>, one has <math display="block">\begin{align} P &= V\Sigma V^*, \\ U &= WV^*, \end{align}</math> where <math>U</math>, <math>V</math>, and <math>W</math> are unitary matrices ([[Orthogonal matrix|orthogonal]] if the field is the reals <math>\mathbb{R}</math>). This confirms that <math>P</math> is positive-definite, and <math>U</math> is unitary. Thus, the existence of the SVD is equivalent to the existence of polar decomposition. One can also decompose <math>A</math> in the form <math display="block"> A = P'U. </math> Here <math>U</math> is the same as before, and <math>P'</math> is given by <math display="block"> P' = UPU^{-1} = (AA^*)^{1/2} = W \Sigma W^*. </math> This is known as the left polar decomposition, whereas the previous decomposition is known as the right polar decomposition. Left polar decomposition is also known as reverse polar decomposition. The '''polar decomposition''' of a square invertible real matrix <math>A</math> is of the form <math display="block"> A = [A] R, </math> where <math>[A] \equiv \left(AA^\mathsf{T}\right)^{1/2}</math> is a [[positive-semidefinite matrix|positive-definite]] [[Hermitian matrix|matrix]], and <math>R = [A]^{-1} A</math> is an orthogonal matrix.
Edit summary
(Briefly describe your changes)
By publishing changes, you agree to the
Terms of Use
, and you irrevocably agree to release your contribution under the
CC BY-SA 4.0 License
and the
GFDL
. You agree that a hyperlink or URL is sufficient attribution under the Creative Commons license.
Cancel
Editing help
(opens in new window)