Open main menu
Home
Random
Recent changes
Special pages
Community portal
Preferences
About Wikipedia
Disclaimers
Incubator escapee wiki
Search
User menu
Talk
Dark mode
Contributions
Create account
Log in
Editing
Normal distribution
(section)
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
=== Infinite divisibility and Cramér's theorem === For any positive integer {{mvar|n}}, any normal distribution with mean {{tmath|\mu}} and variance <math display=inline>\sigma^2</math> is the distribution of the sum of {{mvar|n}} independent normal deviates, each with mean <math display=inline>\frac{\mu}{n}</math> and variance <math display=inline>\frac{\sigma^2}{n}</math>. This property is called [[infinite divisibility (probability)|infinite divisibility]].<ref>{{harvtxt |Patel |Read |1996 |loc=[2.3.6] }}</ref> Conversely, if <math display=inline>X_1</math> and <math display=inline>X_2</math> are independent random variables and their sum <math display=inline>X_1+X_2</math> has a normal distribution, then both <math display=inline>X_1</math> and <math display=inline>X_2</math> must be normal deviates.<ref>{{harvtxt |Galambos |Simonelli |2004 |loc=Theorem 3.5 }}</ref> This result is known as [[Cramér's decomposition theorem]], and is equivalent to saying that the [[convolution]] of two distributions is normal if and only if both are normal. Cramér's theorem implies that a linear combination of independent non-Gaussian variables will never have an exactly normal distribution, although it may approach it arbitrarily closely.<ref name="Bryc 1995 35">{{harvtxt |Bryc |1995 |p=35 }}</ref>
Edit summary
(Briefly describe your changes)
By publishing changes, you agree to the
Terms of Use
, and you irrevocably agree to release your contribution under the
CC BY-SA 4.0 License
and the
GFDL
. You agree that a hyperlink or URL is sufficient attribution under the Creative Commons license.
Cancel
Editing help
(opens in new window)