Editing Absorbed dose (section)

===Dose computation===
The absorbed dose is equal to the radiation exposure (ions or [[coulomb|C]]/kg) of the radiation beam multiplied by the ionization energy of the medium to be ionized.

For example, the ionization energy of dry air at 20&nbsp;°C and 101.325&nbsp;[[pascal (unit)|kPa]] of pressure is {{val|33.97|0.05|u=J/C}}.<ref>{{Cite journal|last1=Boutillon|first1=M|last2=Perroche-Roux|first2=A M|date=1987-02-01|title=Re-evaluation of the W value for electrons in dry air|url=http://stacks.iop.org/0031-9155/32/i=2/a=005?key=crossref.39f54fc0a89c599c170f539f60fb5d2f|journal=Physics in Medicine and Biology|volume=32|issue=2|pages=213–219|doi=10.1088/0031-9155/32/2/005|bibcode=1987PMB....32..213B|s2cid=250751778|issn=0031-9155|url-access=subscription}}</ref> (33.97&nbsp;eV per ion pair) Therefore, an exposure of {{val|2.58|e=-4|u=C/kg}} (1 [[roentgen (unit)|roentgen]]) would deposit an absorbed dose of {{val|8.76|e=-3|u=J/kg}} (0.00876&nbsp;Gy or 0.876&nbsp;rad) in dry air at those conditions.

When the absorbed dose is not uniform, or when it is only applied to a portion of a body or object, an absorbed dose representative of the entire item can be calculated by taking a mass-weighted average of the absorbed doses at each point.

More precisely,{{sfn | ICRP | 2007 | p=1 }}

<math display=block>\overline{D_T} = \frac{\displaystyle \int_{T} D(x,y,z) \, \rho(x,y,z) \, dV} {\displaystyle \int_{T} \rho(x,y,z) \, dV}</math>

Where
*<math>\overline{D_T}</math>  is the mass-averaged absorbed dose of the entire item <math>T</math>;
*<math>T</math>  is the item of interest;
*<math>D(x,y,z)</math>  is the absorbed dose density (absorbed dose per unit volume) as a function of location;
*<math>\rho(x,y,z)</math> is the density (mass per unit volume) as a function of location;
*<math>V</math> is volume.