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Analytic capacity
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==Analytic capacity in terms of Hausdorff dimension== Let dim<sub>''H''</sub> denote [[Hausdorff dimension]] and ''H''<sup>1</sup> denote 1-dimensional [[Hausdorff measure]]. Then ''H''<sup>1</sup>(''K'') = 0 implies ''Ξ³''(''K'') = 0 while dim<sub>''H''</sub>(''K'') > 1 guarantees ''Ξ³''(''K'') > 0. However, the case when dim<sub>''H''</sub>(''K'') = 1 and ''H''<sup>1</sup>(''K'') β (0, β] is more difficult. ===Positive length but zero analytic capacity=== Given the partial correspondence between the 1-dimensional Hausdorff measure of a compact subset of '''C''' and its analytic capacity, it might be conjectured that ''Ξ³''(''K'') = 0 implies ''H''<sup>1</sup>(''K'') = 0. However, this conjecture is false. A counterexample was first given by [[Anatoli Georgievich Vitushkin|A. G. Vitushkin]], and a much simpler one by [[John B. Garnett]] in his 1970 paper. This latter example is the '''linear four corners Cantor set''', constructed as follows: Let ''K''<sub>0</sub> := [0, 1] Γ [0, 1] be the unit square. Then, ''K''<sub>1</sub> is the union of 4 squares of side length 1/4 and these squares are located in the corners of ''K''<sub>0</sub>. In general, ''K<sub>n</sub>'' is the union of 4<sup>''n''</sup> squares (denoted by <math>Q_n^j</math>) of side length 4<sup>β''n''</sup>, each <math>Q_n^j</math> being in the corner of some <math>Q_{n-1}^k</math>. Take ''K'' to be the intersection of all ''K''<sub>''n''</sub> then <math>H^1(K)=\sqrt{2}</math> but ''Ξ³''(''K'') = 0. ===Vitushkin's conjecture=== Let ''K'' β '''C''' be a compact set. Vitushkin's conjecture states that :<math> \gamma(K)=0\ \iff \ \int_0^\pi \mathcal H^1(\operatorname{proj}_\theta(K)) \, d\theta = 0 </math> where <math>\operatorname{proj}_\theta(x,y) := x \cos \theta + y\sin\theta</math> denotes the orthogonal projection in direction ΞΈ. By the results described above, Vitushkin's conjecture is true when dim<sub>''H''</sub>''K'' β 1. [[Guy David (mathematician)|Guy David]] published a proof in 1998 of Vitushkin's conjecture for the case dim<sub>''H''</sub>''K'' = 1 and ''H''<sup>1</sup>(''K'') < β. In 2002, [[Xavier Tolsa]] proved that analytic capacity is countably semiadditive. That is, there exists an absolute constant ''C'' > 0 such that if ''K'' β '''C''' is a compact set and <math>K = \bigcup_{i=1}^\infty K_i</math>, where each ''K''<sub>''i''</sub> is a Borel set, then <math>\gamma(K) \leq C \sum_{i=1}^\infty\gamma(K_i)</math>. David's and Tolsa's theorems together imply that Vitushkin's conjecture is true when ''K'' is ''H''<sup>1</sup>-[[sigma-finite]]. In the non ''H''<sup>1</sup>-sigma-finite case, Pertti Mattila proved in 1986<ref>{{Cite journal |last=Mattila |first=Pertti |date=1986 |title=Smooth Maps, Null-Sets for Integralgeometric Measure and Analytic Capacity |url=https://www.jstor.org/stable/1971273 |journal=Annals of Mathematics |volume=123 |issue=2 |pages=303β309 |doi=10.2307/1971273 |jstor=1971273 |issn=0003-486X|url-access=subscription }}</ref> that the conjecture is false, but his proof did not specify which implication of the conjecture fails. Subsequent work by Jones and Muray<ref>{{Cite journal |last1=Jones |first1=Peter W. |last2=Murai |first2=Takafumi |title=Positive analytic capacity but zero Buffon needle probability. |url=https://msp.org/pjm/1988/133-1/pjm-v133-n1-p06-s.pdf |journal=Pacific Journal of Mathematics |date=1988 |volume=133 |issue=1 |pages=99β114|doi=10.2140/pjm.1988.133.99 }}</ref> produced an example of a set with zero Favard length and positive analytic capacity, explicitly disproving one of the directions of the conjecture. As of 2023 it is not known whether the other implication holds but some progress has been made towards a positive answer by Chang and Tolsa.<ref>{{Cite journal |last1=Chang |first1=Alan |last2=Tolsa |first2=Xavier |date=2020-10-05 |title=Analytic capacity and projections |url=https://ems.press/doi/10.4171/jems/1004 |journal=Journal of the European Mathematical Society |language=en |volume=22 |issue=12 |pages=4121β4159 |doi=10.4171/JEMS/1004 |issn=1435-9855|arxiv=1712.00594 }}</ref>
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