Open main menu
Home
Random
Recent changes
Special pages
Community portal
Preferences
About Wikipedia
Disclaimers
Incubator escapee wiki
Search
User menu
Talk
Dark mode
Contributions
Create account
Log in
Editing
Homotopy group
(section)
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
== Long exact sequence of a fibration == Let <math>p : E \to B</math> be a basepoint-preserving [[Serre fibration]] with fiber <math>F,</math> that is, a map possessing the [[homotopy lifting property]] with respect to [[CW complex]]es. Suppose that ''B'' is path-connected. Then there is a long [[exact sequence]] of homotopy groups <math display="block">\cdots \to \pi_n(F) \to \pi_n(E) \to \pi_n(B) \to \pi_{n-1}(F) \to \cdots \to \pi_0(E) \to 0.</math> Here the maps involving <math>\pi_0</math> are not [[group homomorphism]]s because the <math>\pi_0</math> are not groups, but they are exact in the sense that the [[Image (mathematics)|image]] equals the [[Kernel (algebra)|kernel]]. Example: the [[Hopf fibration]]. Let ''B'' equal <math>S^2</math> and ''E'' equal <math>S^3.</math> Let ''p'' be the [[Hopf fibration]], which has fiber <math>S^1.</math> From the long exact sequence <math display="block">\cdots \to \pi_n(S^1) \to \pi_n(S^3) \to \pi_n(S^2) \to \pi_{n-1} (S^1) \to \cdots</math> and the fact that <math>\pi_n(S^1) = 0</math> for <math>n \geq 2,</math> we find that <math>\pi_n(S^3) = \pi_n(S^2)</math> for <math>n \geq 3.</math> In particular, <math>\pi_3(S^2) = \pi_3(S^3) = \Z.</math> In the case of a cover space, when the fiber is discrete, we have that <math>\pi_n(E)</math> is isomorphic to <math>\pi_n(B)</math> for <math>n > 1,</math> that <math>\pi_n(E)</math> embeds [[injective]]ly into <math>\pi_n(B)</math> for all positive <math>n,</math> and that the [[subgroup]] of <math>\pi_1(B)</math> that corresponds to the embedding of <math>\pi_1(E)</math> has cosets in [[bijection]] with the elements of the fiber. When the fibration is the [[homotopy fiber|mapping fibre]], or dually, the cofibration is the [[mapping cone (topology)|mapping cone]], then the resulting exact (or dually, coexact) sequence is given by the [[Puppe sequence]]. === Homogeneous spaces and spheres === There are many realizations of spheres as [[homogeneous space]]s, which provide good tools for computing homotopy groups of Lie groups, and the classification of principal bundles on spaces made out of spheres. ==== Special orthogonal group ==== There is a fibration<ref> {{cite book | last1=Husemoller | first1=Dale | title=Fiber Bundles | series=Graduate Texts in Mathematics | volume=20 | date=1994 | publisher=Springer | doi=10.1007/978-1-4757-2261-1 | doi-access=free | page=89 | isbn=978-1-4757-2263-5 }}</ref> <math display="block">\mathrm{SO}(n-1) \to \mathrm{SO}(n) \to \mathrm{SO}(n) / \mathrm{SO}(n-1) \cong S^{n-1}</math> giving the long exact sequence <math display="block">\cdots \to \pi_i(\mathrm{SO}(n-1)) \to \pi_i(\mathrm{SO}(n)) \to \pi_i\left(S^{n-1}\right) \to \pi_{i-1}(\mathrm{SO}(n-1)) \to \cdots</math> which computes the low order homotopy groups of <math>\pi_i(\mathrm{SO}(n-1)) \cong \pi_i(\mathrm{SO}(n))</math> for <math>i < n-1,</math> since <math>S^{n-1}</math> is <math>(n-2)</math>-connected. In particular, there is a fibration <math display="block">\mathrm{SO}(3) \to \mathrm{SO}(4) \to S^3</math> whose lower homotopy groups can be computed explicitly. Since <math>\mathrm{SO}(3) \cong \mathbb{RP}^3,</math> and there is the fibration <math display="block">\Z/2 \to S^n \to \mathbb{RP}^n</math> we have <math>\pi_i(\mathrm{SO}(3)) \cong \pi_i(S^3)</math> for <math>i > 1.</math> Using this, and the fact that <math>\pi_4\left(S^3\right) = \Z/2,</math> which can be computed using the [[Postnikov system]], we have the long exact sequence <math display="block">\begin{align} \cdots \to{} &\pi_4(\mathrm{SO}(3)) \to \pi_4(\mathrm{SO}(4)) \to \pi_4(S^3) \to \\ \to{} &\pi_3(\mathrm{SO}(3)) \to \pi_3(\mathrm{SO}(4)) \to \pi_3(S^3) \to \\ \to{} &\pi_2(\mathrm{SO}(3)) \to \pi_2(\mathrm{SO}(4)) \to \pi_2(S^3) \to \cdots \\ \end{align}</math> Since <math>\pi_2\left(S^3\right) = 0</math> we have <math>\pi_2(\mathrm{SO}(4)) = 0.</math> Also, the middle row gives <math>\pi_3(\mathrm{SO}(4)) \cong \Z\oplus\Z</math> since the connecting map <math>\pi_4\left(S^3\right) = \Z/2 \to \Z = \pi_3\left(\mathbb{RP}^3\right)</math> is trivial. Also, we can know <math>\pi_4(\mathrm{SO}(4))</math> has two-torsion. ===== Application to sphere bundles ===== Milnor<ref>{{cite journal|last=Milnor|first=John|date=1956|title=On manifolds homeomorphic to the 7-sphere|journal=Annals of Mathematics|volume=64|issue=2 |pages=399β405|doi=10.2307/1969983 |jstor=1969983 }}</ref> used the fact <math>\pi_3(\mathrm{SO}(4)) = \Z\oplus\Z</math> to classify 3-sphere bundles over <math>S^4,</math> in particular, he was able to find [[exotic sphere]]s which are [[smooth manifold]]s called [[Milnor's sphere|Milnor's spheres]] only homeomorphic to <math>S^7,</math> not [[diffeomorphic]]. Note that any sphere bundle can be constructed from a <math>4</math>-[[vector bundle]], which have structure group <math>\mathrm{SO}(4)</math> since <math>S^3</math> can have the structure of an [[Oriented manifold|oriented]] [[Riemannian manifold]]. === Complex projective space === There is a fibration <math display="block">S^1 \to S^{2n+1} \to \mathbb{CP}^n</math> where <math>S^{2n+1}</math> is the unit sphere in <math>\Complex^{n+1}.</math> This sequence can be used to show the simple-connectedness of <math>\mathbb{CP}^n</math> for all <math>n.</math>
Edit summary
(Briefly describe your changes)
By publishing changes, you agree to the
Terms of Use
, and you irrevocably agree to release your contribution under the
CC BY-SA 4.0 License
and the
GFDL
. You agree that a hyperlink or URL is sufficient attribution under the Creative Commons license.
Cancel
Editing help
(opens in new window)