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Incompressible flow
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== Difference from material == As defined earlier, an incompressible (isochoric) flow is the one in which :<math> \nabla \cdot \mathbf u = 0. \, </math> This is equivalent to saying that :<math> \frac{D\rho}{Dt} = \frac{\partial \rho}{\partial t} + \mathbf u \cdot \nabla \rho = 0</math> i.e. the [[Substantive derivative|material derivative]] of the density is zero. Thus if one follows a material element, its mass density remains constant. Note that the material derivative consists of two terms. The first term <math> \tfrac{\partial \rho}{\partial t} </math> describes how the density of the material element changes with time. This term is also known as the ''unsteady term''. The second term, <math>\mathbf u \cdot \nabla \rho</math> describes the changes in the density as the material element moves from one point to another. This is the ''advection term'' (convection term for scalar field). For a flow to be accounted as bearing incompressibility, the accretion sum of these terms should vanish. On the other hand, a '''homogeneous, incompressible material''' is one that has constant density throughout. For such a material, <math>\rho = \text{constant} </math>. This implies that, :<math> \frac{\partial \rho}{\partial t} = 0 </math> and :<math>\nabla \rho = 0</math> ''independently''. From the continuity equation it follows that :<math> \frac{D\rho}{Dt} = \frac{\partial \rho}{\partial t} + \mathbf u \cdot \nabla \rho = 0 \ \Rightarrow\ \nabla \cdot \mathbf u = 0 </math> Thus homogeneous materials always undergo flow that is incompressible, but the converse is not true. That is, compressible materials might not experience compression in the flow.
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