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Law of total tricks
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==Examples== For example, suppose that North-South have an eight-card heart fit and East-West have an eight-card spade fit. The total number of trumps is 16 so the "law" says the total number of tricks is also 16. That is, if North-South can take eight tricks playing in hearts, then East-West can take 16 - 8 = 8 tricks playing in spades; if North-South can take nine tricks in hearts, LoTT says East-West can take only seven tricks in spades. {{BridgeHandNWES |Label = |Lead = |K Q 8 5 3|K 4 3|7|J 10 4 3 |10 7|A 8 7 6 5|J 9 4|K Q 9 |J 4|10 9 2|K Q 10 3|A 8 7 2 |A 9 6 2|Q J|A 8 6 5 2|6 5}} In the [[contract bridge diagram|diagram]], N-S have 9 spades and E-W 8 hearts combined. N-S can make 4 spades (conceding two clubs and heart ace) while E-W can make only 1 heart on a good defense (which takes a trump from QJ, two spades, diamond ace and two diamond ruffs)βthe law holds, as the total tricks available is 10+7=17. Note, however, how minor card rearrangements affect the law: {| | #If the N-S diamonds were divided 4-2 instead of 5-1, with clubs consequently divided 3-3, the available total tricks would be only 8 for N-S + 8 for E-W = 16 #If, on the other hand, the E-W spades were divided 3-1 instead of 2-2 (with appropriate minor-suit rearrangement), they could make 2{{Hearts}}, while N-S could still make 4{{Spades}}, giving 18 total tricks. |} {{Clear}} ===Consequences=== There are a number of bridge conventions that take advantage of this principle. For example, [[Bergen raises]] following an opening bid of one of a major (using a 5-card major system): * 3 of the major = 4-card support and 0-6 HCP * 3C = 4-card support and 7-9 points * 3D = 4-card support and 10-12 HCP In 2002, [[Anders Wirgren]] called the accuracy of the "law" into question, saying it works on only 35-40% of deals. However, Larry Cohen remains convinced it is a useful guideline, especially when adjustments are used properly. Mendelson (1998) finds that it is "accurate to within one trick on the vast majority of hands"
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