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Parabolic trajectory
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==Barker's equation== Barker's equation relates the time of flight <math>t</math> to the true anomaly <math>\nu</math> of a parabolic trajectory:<ref> {{cite book | last1 = Bate | first1 = Roger | last2 = Mueller | first2 = Donald | last3 = White | first3 = Jerry | title = Fundamentals of Astrodynamics | url = https://archive.org/details/fundamentalsofas00bate | url-access = registration | publisher = Dover Publications, Inc., New York | year = 1971 | isbn = 0-486-60061-0 }} p 188</ref> :<math>t - T = \frac{1}{2} \sqrt{\frac{p^3}{\mu}} \left(D + \frac{1}{3} D^3 \right)</math> where: *<math>D = \tan \frac{\nu}{2}</math> is an auxiliary variable *<math>T</math> is the time of periapsis passage *<math>\mu</math> is the standard gravitational parameter *<math>p</math> is the [[conic section#Features|semi-latus rectum]] of the trajectory (<math>p = h^2/\mu</math> ) More generally, the time (epoch) between any two points on an orbit is :<math> t_f - t_0 = \frac{1}{2} \sqrt{\frac{p^3}{\mu}} \left(D_f + \frac{1}{3} D_f^3 - D_0 - \frac{1}{3} D_0^3\right) </math> Alternately, the equation can be expressed in terms of periapsis distance, in a parabolic orbit <math>r_p = p/2</math>: :<math>t - T = \sqrt{\frac{2 r_p^3}{\mu}} \left(D + \frac{1}{3} D^3\right)</math> Unlike [[Kepler's equation]], which is used to solve for true anomalies in elliptical and hyperbolic trajectories, the true anomaly in Barker's equation can be solved directly for <math>t</math>. If the following substitutions are made :<math>\begin{align} A &= \frac{3}{2} \sqrt{\frac{\mu}{2r_p^3}} (t - T) \\[3pt] B &= \sqrt[3]{A + \sqrt{A^{2}+1}} \end{align}</math> then : <math>\nu = 2\arctan\left(B - \frac{1}{B}\right)</math> With hyperbolic functions the solution can be also expressed as:<ref>{{cite journal | last1 = Zechmeister | first1 = Mathias | title = Solving Kepler's equation with CORDIC double iterations | journal = MNRAS | date = 2020 | volume= 500 | issue = 1 | pages = 109β117 | doi = 10.1093/mnras/staa2441 | doi-access = free | arxiv = 2008.02894 | bibcode = 2021MNRAS.500..109Z }} Eq.(40) and Appendix C.</ref> : <math>\nu = 2\arctan\left(2\sinh\frac{\mathrm{arcsinh} \frac{3M}{2}}{3}\right)</math> where : <math> M = \sqrt{\frac{\mu}{2r_p^3}} (t - T)</math>
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