Open main menu
Home
Random
Recent changes
Special pages
Community portal
Preferences
About Wikipedia
Disclaimers
Incubator escapee wiki
Search
User menu
Talk
Dark mode
Contributions
Create account
Log in
Editing
Standard rate turn
(section)
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
=== Angle of bank formula === The formula for calculating the angle of bank for a specific [[true airspeed]] (TAS) in SI units (or other [[coherent system]]) is:<ref>[http://www.luizmonteiro.com/Article_Bank_Angle_for_Std_Rate_01.aspx LuizMonteiro.com Aviation Education]</ref> <math>\phi = \arctan \frac{v_\mathrm{t}^2}{rg}</math> where <math>\phi</math> is the angle of bank, <math>v_\mathrm{t}</math> is true airspeed, <math>r</math> is the radius of the turn, and <math>g</math> is the acceleration due to gravity. For a rate-one turn and velocity in [[Knot (unit)|knots]] ([[nautical mile]]s per hour, symbol kn), this comes to <math>\phi = \arctan \frac{\{v_\mathrm{t}\}_\mathrm{kn}} {364}</math>. A convenient approximation for the bank angle in degrees is <math>\phi / ^\circ \approx \frac{\{v_\mathrm{t}\}_\mathrm{kn}} {10} + 7</math> For aircraft holding purposes, the [[International Civil Aviation Organization]] (ICAO) mandates that all turns should be made, "at a bank angle of 25Β° or at a rate of 3Β° per second, whichever requires the lesser bank."<ref>{{cite book |title=Doc 8168 (PANS-OPS) |edition=5 |year=2006 |publisher=ICAO }}</ref> By the above formula, a rate-one turn at a TAS greater than 180 knots would require a bank angle of more than 25Β°. Therefore, faster aircraft just use 25Β° for their turns.
Edit summary
(Briefly describe your changes)
By publishing changes, you agree to the
Terms of Use
, and you irrevocably agree to release your contribution under the
CC BY-SA 4.0 License
and the
GFDL
. You agree that a hyperlink or URL is sufficient attribution under the Creative Commons license.
Cancel
Editing help
(opens in new window)