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Star polygon
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====Degenerate regular star polygons==== If ''p'' and ''q'' are not coprime, a degenerate polygon will result with coinciding vertices and edges. For example, {6/2} will appear as a triangle, but can be labeled with two sets of vertices: 1–3 and 4–6. This should be seen not as two overlapping triangles, but as a double-winding single unicursal hexagon.<ref>[http://www.math.washington.edu/~grunbaum/Your%20polyhedra-my%20polyhedra.pdf Are Your Polyhedra the Same as My Polyhedra?] {{Webarchive|url=https://web.archive.org/web/20160803160413/http://www.math.washington.edu/~grunbaum/Your%20polyhedra-my%20polyhedra.pdf |date=2016-08-03 }}, Branko Grünbaum</ref><ref>Coxeter, The Densities of the Regular Polytopes I, p. 43:<BR>If ''q'' is odd, the truncation of {''p''/''q''} is naturally {2''p''/''q''}. But if ''q'' is even, the truncation of {''p''/''q''} consists of two coincident {{nowrap|{''p''/(''q''/2)}'s;}} two, because each side arises once from an original side and once from an original vertex. Since {{nowrap|2(''q''/2) {{=}} ''q'',}} the density of a polygon is never altered by truncation.</ref> :[[File:Doubly wound hexagon.svg|160px]]
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