Open main menu
Home
Random
Recent changes
Special pages
Community portal
Preferences
About Wikipedia
Disclaimers
Incubator escapee wiki
Search
User menu
Talk
Dark mode
Contributions
Create account
Log in
Editing
Trapdoor function
(section)
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
===Rabin's quadratic residue assumption=== Let <math>n</math> be a large composite number such that <math>n = pq</math>, where <math>p</math> and <math>q</math> are large primes such that <math>p \equiv 3 \pmod{4}, q \equiv 3 \pmod{4}</math>, and kept confidential to the adversary. The problem is to compute <math>z</math> given <math>a</math> such that <math>a \equiv z^2 \pmod{n}</math>. The trapdoor is the factorization of <math>n</math>. With the trapdoor, the solutions of ''z'' can be given as <math>cx + dy, cx - dy, -cx + dy, -cx - dy</math>, where <math>a \equiv x^2 \pmod{p}, a \equiv y^2 \pmod{q}, c \equiv 1 \pmod{p}, c \equiv 0 \pmod{q}, d \equiv 0 \pmod{p}, d \equiv 1 \pmod{q}</math>. See [[Chinese remainder theorem]] for more details. Note that given primes <math>p</math> and <math>q</math>, we can find <math>x \equiv a^{\frac{p+1}{4}} \pmod{p}</math> and <math>y \equiv a^{\frac{q+1}{4}} \pmod{q}</math>. Here the conditions <math>p \equiv 3 \pmod{4}</math> and <math>q \equiv 3 \pmod{4}</math> guarantee that the solutions <math>x</math> and <math>y</math> can be well defined.<ref>Goldwasser's lecture notes, 2.3.4.</ref>
Edit summary
(Briefly describe your changes)
By publishing changes, you agree to the
Terms of Use
, and you irrevocably agree to release your contribution under the
CC BY-SA 4.0 License
and the
GFDL
. You agree that a hyperlink or URL is sufficient attribution under the Creative Commons license.
Cancel
Editing help
(opens in new window)