Open main menu
Home
Random
Recent changes
Special pages
Community portal
Preferences
About Wikipedia
Disclaimers
Incubator escapee wiki
Search
User menu
Talk
Dark mode
Contributions
Create account
Log in
Editing
Differentiable function
(section)
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
==Differentiability in higher dimensions== A [[function of several real variables]] {{math|'''f''': '''R'''<sup>''m''</sup> β '''R'''<sup>''n''</sup>}} is said to be differentiable at a point {{math|'''x'''<sub>0</sub>}} if [[there exists]] a [[linear map]] {{math|'''J''': '''R'''<sup>''m''</sup> β '''R'''<sup>''n''</sup>}} such that :<math>\lim_{\mathbf{h}\to \mathbf{0}} \frac{\|\mathbf{f}(\mathbf{x_0}+\mathbf{h}) - \mathbf{f}(\mathbf{x_0}) - \mathbf{J}\mathbf{(h)}\|_{\mathbf{R}^{n}}}{\| \mathbf{h} \|_{\mathbf{R}^{m}}} = 0.</math> If a function is differentiable at {{math|'''x'''<sub>0</sub>}}, then all of the [[partial derivative]]s exist at {{math|'''x'''<sub>0</sub>}}, and the linear map {{math|'''J'''}} is given by the [[Jacobian matrix]], an ''n'' Γ ''m'' matrix in this case. A similar formulation of the higher-dimensional derivative is provided by the [[fundamental increment lemma]] found in single-variable calculus. If all the partial derivatives of a function exist in a [[Neighbourhood (mathematics)|neighborhood]] of a point {{math|'''x'''<sub>0</sub>}} and are continuous at the point {{math|'''x'''<sub>0</sub>}}, then the function is differentiable at that point {{math|'''x'''<sub>0</sub>}}. However, the existence of the partial derivatives (or even of all the [[directional derivative]]s) does not guarantee that a function is differentiable at a point. For example, the function {{math|''f'': '''R'''<sup>2</sup> β '''R'''}} defined by :<math display="block">f(x,y) = \begin{cases}x & \text{if }y \ne x^2 \\ 0 & \text{if }y = x^2\end{cases}</math> is not differentiable at {{math|(0, 0)}}, but all of the partial derivatives and directional derivatives exist at this point. For a continuous example, the function :<math>f(x,y) = \begin{cases}y^3/(x^2+y^2) & \text{if }(x,y) \ne (0,0) \\ 0 & \text{if }(x,y) = (0,0)\end{cases}</math> is not differentiable at {{math|(0, 0)}}, but again all of the partial derivatives and directional derivatives exist. {{See also|Multivariable calculus|Smoothness#Multivariate differentiability classes}}
Edit summary
(Briefly describe your changes)
By publishing changes, you agree to the
Terms of Use
, and you irrevocably agree to release your contribution under the
CC BY-SA 4.0 License
and the
GFDL
. You agree that a hyperlink or URL is sufficient attribution under the Creative Commons license.
Cancel
Editing help
(opens in new window)